Answer:
132 N
Explanation:
newton's second law states that force = mass * acceleration
F = ma
plug in 66 kg for mass and 2 m/s^2 for acceleration
F = 66 * 2
F = 132 N
Quantitative because it tells you how many wheels
Answer:

Explanation:
Let assume that cooling water works under a pressure of 1 atmosphere. The time required to boil half of the water is determined by the First Law of Thermodynamics:
![\dot Q \cdot \Delta t = m \cdot [c_{p,w}\cdot (T_{2}-T_{1})+h_{fg}]](https://tex.z-dn.net/?f=%5Cdot%20Q%20%5Ccdot%20%5CDelta%20t%20%3D%20m%20%5Ccdot%20%5Bc_%7Bp%2Cw%7D%5Ccdot%20%28T_%7B2%7D-T_%7B1%7D%29%2Bh_%7Bfg%7D%5D)
![\Delta t = \frac{m\cdot [c_{p,w}\cdot (T_{2}-T_{1})+h_{fg}]}{\dot Q}](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20%5Cfrac%7Bm%5Ccdot%20%5Bc_%7Bp%2Cw%7D%5Ccdot%20%28T_%7B2%7D-T_%7B1%7D%29%2Bh_%7Bfg%7D%5D%7D%7B%5Cdot%20Q%7D)
![\Delta t = \frac{(2.25\times 10^{5}\,kg)\left[\left(4.186\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (100\,^{\textdegree}C - 10\,^{\textdegree}C)+2256.5\,\frac{kJ}{kg} \right]}{200000\,kW}](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20%5Cfrac%7B%282.25%5Ctimes%2010%5E%7B5%7D%5C%2Ckg%29%5Cleft%5B%5Cleft%284.186%5C%2C%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20%5E%7B%5Ctextdegree%7DC%7D%20%5Cright%29%5Ccdot%20%28100%5C%2C%5E%7B%5Ctextdegree%7DC%20-%2010%5C%2C%5E%7B%5Ctextdegree%7DC%29%2B2256.5%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D%20%5Cright%5D%7D%7B200000%5C%2CkW%7D)

The maximum height is reached when the vertical component of the velocity is zero.
vertical direction:
acceleration: a = -g = -9.81m/s²
velocity: v = -g*t + v₀
position: y = -0.5*g*t² + v₀*t + y₀
For v= 0:
0 = -g*t + v₀ => t = v₀/g
Insert into position equation gives:
y(max) = (-0.5*v₀²/g) + (v₀²/g) + y₀ = (0.5*v₀²/g) + y₀
Answer:
lower
Explanation:
The lower the value of the coefficient of friction, the lower the resistance to sliding.
The coefficient of friction is the ratio of the frictional force and the normal force pressing two surfaces in contact together.
U =
U is the coefficient of friction
F is the frictional force
N is the normal force
We see that coefficient of friction is directly proportional to frictional force.