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Nutka1998 [239]
3 years ago
15

a rock is blown out of a volcano when it started to fall from its highest point at 9.5 seconds to hit the ground​

Physics
1 answer:
tatyana61 [14]3 years ago
3 0

Answer:

<em>The rock reaches a maximum height of 442.225 m and was thrown at a speed of 93.1 m/s</em>

Explanation:

<u>Vertical Launch</u>

The rock is launched up with a certain speed vo, it reaches its highest point at a height h when the speed is zero, and then it stars a free-fall motion until it hits the ground at time t.

The maximum height is given by

\displaystyle h=\frac{g\cdot t^2}{2}

The rock takes the same time to reach this point as to return to the ground, thus we can calculate the maximum height

\displaystyle h=\frac{9.8\cdot 9.5^2}{2}=442.225\ m

The rock was thrown up at a speed

v_o=gt=9.8\cdot 9.5=93.1 \ m/s

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b) dưới dạng a = Δv / t

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v = 0,2 × 40

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do đó d = vt

d = 8 × 40

d = 320m

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<u>Answer</u><u>:</u>

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Hope you could get an idea from here.

Doubt clarification - use comment section.

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