<em>Matter is composed of elementary particles i.e. quarks and leptons.</em>
<em>Matter is composed of elementary particles i.e. quarks and leptons.Matter is composed of elementary particles which is called quarks and leptons. Quarks consist of protons, neutrons and electrons. All observable matter is made up of up quarks, down quarks and electrons.</em>
<em>Matter is composed of elementary particles i.e. quarks and leptons.Matter is composed of elementary particles which is called quarks and leptons. Quarks consist of protons, neutrons and electrons. All observable matter is made up of up quarks, down quarks and electrons.Lepton is an elementary particle consist of half-integer spin that does not undergo strong interactions. Leptons exist on two main classes i.e. charged leptons, and neutral leptons. Electron, electron neutrino, muon, muon neutrino, tau and tau neutrino are the six types of leptons.</em>
We have: Energy(E) = Planck's constant(h) × Frequency(∨)
Here, Planck's constant(h) = 6.626 × 10⁻³⁴ J/s
Frequency (∨) = 3.16 × 10¹² /s
Substitute the values into the expression:
E = (6.626 × 10⁻³⁴)(3.16 × 10¹²) J
E = 2.093 × 10⁻²¹ Joules
In short, Your Final answer would be 2.093 × 10⁻²¹ J
Hope this helps!
Answer: Stars are in space for very long time, much longer than that one night. You are looking back in time because those stars have been there for so long that it’s like looking back in time, to when those stars were there.
Explanation:
May I please have brainlest
Answer:
The total momentum after the collision is 1 kg-m/s.
Explanation:
We have,
Mass of a steel sphere is 0.5 kg
It is travelling with a speed of 2 m/s
It collides with an identical sphere at rest.
The law of conservation of momentum states that the initial momentum is equal to the final momentum for an isolated system. Here, initial momentum is :
So, the total momentum after the collision is 1 kg-m/s.
Answer:
0.775
Explanation:
The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:
where
G is the gravitational constant
M is the mass of the planet
m is the mass of the object
R is the radius of the planet
For planet A, the weight of the object is
For planet B,
We also know that the weight of the object on the two planets is the same, so
So we can write
We also know that the mass of planet A is only sixty percent that of planet B, so
Substituting,
Now we can elimanate G, MB and m from the equation, and we get
So the ratio between the radii of the two planets is
