The correct value for the rocket speed measured by an observer on earth would be = 14c
<h3>Calculation and of the rocket speed</h3>
To calculate the speed of the rocket we should observe that the rocket and the missile are in a relative motion which are moving on the same direction.
The speed of the rocket = 12c
The speed of the missile = 12c
The individual speed of earth =0c
But, the relative speed of the missile and the Earth is the sum of individual speeds.
Thus, the speed of rocket as measured by an observer on the Earth would be 0 + 14c = 14c.
Therefore, the correct value for the rocket speed measured by an observer on earth would be =14c
Learn more about relative motion here:
brainly.com/question/17228388
#SPJ1
Friction is a force. A resistance force that tries to slow down and stop objects in motion. The difference between friction and air resistance is that friction acts on surfaces. For example, if I were skateboarding on a rough surface, more friction would occur so I would travel slower. If I were skareboarding on ice, I would go faster because there is much less friction to slow me down. Hope that helps:)
This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system
During an exothermic reaction; light and heat are released into the environment.
An exothermic reaction is one in which heat is released to the environment. This heat can be physically observed sometimes like in an a combustion reaction.
In an exothermic reaction, the enthalpy of the reactants is greater than the enthalpy of the products.
This heat lost is sometimes felt as the hotness of the vessel in which the reaction has taken place.
In conclusion, light and heat are released into the environment in an exothermic reaction.
Learn more: brainly.com/question/4345448
Answer:
angular acceleration is -0.2063 rad/s²
Explanation:
Given data
mass m = 95.2 kg
radius r = 0.399 m
turning ω = 93 rpm
radial force N = 19.6 N
kinetic coefficient of friction μ = 0.2
to find out
angular acceleration
solution
we know frictional force that is = radial force × kinetic coefficient of friction
frictional force = 19.6 × 0.2
frictional force = 3.92 N
and
we know moment of inertia that is
γ = I ×α = frictional force × r
so
γ = 1/2 mr²α
α = -2f /mr
α = -2(3.92) /95.2 (0.399)
α = - 7.84 / 37.9848 = -0.2063
so angular acceleration is -0.2063 rad/s²
