Question

the length of a rectangle is 4 more than the width, if the perimeter of the rectangle is 100 feet find the length width and area

Answer 1

Answer:

$Length=27feet\\Width=23feet$

Area=$621feet^2$

Step-by-step explanation:

Perimeter of the rectangle= 100 feet

Let, the width of the rectangle be 'w'

Length=w+4

Perimeter=2(Length+width)

    $100= 2(w+4+w)\\\\100=2(2w+4)\\\\100/2=2w+4\\\\50=2w+4\\\\2w+50-4\\\\2w=46\\\\w=23 feet\\\\Width=23 feet$

Length=w+4=23+4=27 feet

$Length=27feet\\Width=23feet$

Area of a rectangle = Length*Width

                               $=27*23\\\\=621Feet^2$

        Area=$621feet^2$