Answer:
11.58 L of N₂
Explanation:
We'll begin by calculating the number of mole in 37.2 g of magnesium. This can be obtained as follow:
Mass of Mg = 37.2 g
Molar mass of Mg = 24 g/mol
Mole of Mg =?
Mole = mass /Molar mass
Mole of Mg = 37.2 / 24
Mole of Mg = 1.55 moles
Next, we shall write the balanced equation for the reaction. This is illustrated below:
3Mg + N₂ —> Mg₃N₂
From the balanced equation above,
3 moles of Mg reacted with 1 mole of N₂.
Therefore, 1.55 moles of Mg will react with = (1.55 × 1)/3 = 0.517 mole of N₂
Thus, 0.517 mole of N₂ is need for the reaction.
Finally, we shall determine the volume of N₂ needed for the reaction as follow:
Recall:
1 mole of a gas occupies 22.4 L at STP.
1 mole of N₂ occupied 22.4 L at STP.
Therefore, 0.517 mole of N₂ will occupy = 0.517 × 22.4 = 11.58 L at STP
Thus, 11.58 L of N₂ is needed for the reaction.
Answer:
Shape- square planar , hybridisation-sp3
Explanation:
Shape:
- VSPER theorey is used to determine both electron geometry and molecular geometry of a molecule.(PtCl4)2 molecular geometry is square planar
- Hybridisation:It undergoes sp3 hybridisation.since there are 2 unpaired electrons in this case, it is paramagnetic in nature
-
Answer:
78.4%
Explanation:
yield = actual/theoretical = 7.84/10 = 78.4%
<u>Answer:</u> The percent composition of in taconite is 37.6 %.
<u>Explanation:</u>
We are given:
Mass of taconite pellets = 1 ton = 907185 g (Conversion factor: 1 ton = 907185 g)
Mass of iron produced = 545 lb = 247212 g (Conversion factor: 1 lb = 453.6 g )
We know that:
Molar mass of iron = 55.85 g/mol
Molar mass of = 231.53 g/mol
1 mole of contains 3 moles of iron atom and 4 moles of oxygen atom
(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of
So, 247212 grams of iron will be produced from = of
To calculate the percentage of in taconite, we use the equation:
Mass of taconite = 907185 g
Mass of = 341611.43 g
Putting values in above equation, we get:
Hence, the percent composition of in taconite is 37.6 %.
Dry and desert conditions