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PIT_PIT [208]
3 years ago
11

Let this be an easy 5 points for your brainly account all is ask for in return is a "thank you"

Chemistry
1 answer:
Svet_ta [14]3 years ago
4 0

Answer:

The number of neutrons present in one atom of isotope of Silicon of mass 28 amu is<u> 14 neutrons</u>

Explanation:

Symbol of Si isotope

_{14}^{28}\textrm{Si}

<u>Number of Neutron = Mass number - Atomic Number</u>

Mass number = Total number of protons and neutrons present in the nucleus of the atom.For Si = 28 amu

Atomic Number = Total number of Protons present in the nucleus.

Si = 14

Number of neutron = 24 - 14

                                = 14

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Clo3− draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show t
Karo-lina-s [1.5K]

The formal charges of all nonhydrogen atoms are -1.

Solution:-

<u>O 7-4 = 3 O Double bond on one H 5-4 = 1</u>

O-Cl-O 6-7 = -1x4 = -4 N 5-4=1 H-N-H 1-1=0

O 3-4= -1 O O 6-7 = -1(2)=-2 H 1-0=+1

<u>6-6 = 0 1-2 = -1</u>

It will percentage its last valence electron thru a single bond to the terminal oxygen atom. This is in agreement with carbon and hydrogen atoms that each need to form 4 and 1 covalent bonds respectively. because the terminal oxygen atom best has a single covalent bond, it'll have a proper rate of -1.

According to the lewis structure of SO2, The critical atom is sulfur and it is bonded with 2 oxygen atoms thru a double bond. each oxygen atom acquires 2 lone pairs of electrons and the primary sulfur atom has 1 lone pair of electrons.

Learn more about Nonhydrogen atoms here:-brainly.com/question/2822744

#SPJ4

3 0
2 years ago
Consider the chemical equation. CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl What is the percent yield of NaCl if 31.0 g of CuCl2
lana [24]
CuCl2 + 2NaNO3 ---->  Cu(NO3)2 + 2NaCl

using molar masses:-
Theoretical yields:-
63.54 + 2(35.45) g  of CuCl2  produces  2(22.98 + 35.45) g of NaCl
    134.44  g .................................................... 116.86 g
       31.0 g ....................................................31.0 * 116.86 /134.44=26.95g  
 
 So percentage yield is 21.2* 100 / 26.95    =  78.7%  to nearest tenth                                                                                                              


5 0
4 years ago
Read 2 more answers
Butane (C4 H10(g), Hf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Hf = –393.5 kJ/mol ) and water (H2 O,
WITCHER [35]

Answer: Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

Explanation:

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+4O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]

We are given:

\Delta H^o_f_{(C_4H_{10}(g))}=-125.6kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ

Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

6 0
3 years ago
Merits of modern periodic table?​
ANEK [815]

Answer:

<h3>Merits of modern periodic table:</h3>
  • The wrong position of some elements like argon, potassium, cobalt and nickel due to atomic weights have been solved by arranging the elements in the order of increasing atomic number without changing their own places.
  • The isotopes of some element have the same atomic numbers. Therefore, they find the same position in periodic table.
  • It separates metals from non-metals.
  • The groups of the table are divided into sub groups A and B due to their dissimilar properties which make the study of elements specific and easier.
  • The representative and transition elements have been separated.

Hope this helps...

Good luck on your assignment...

6 0
3 years ago
Determine the mass of 2.4 x 10^24 atoms of gold?​
Scorpion4ik [409]

Answer:

Mass = 785.9 g

Explanation:

Given data:

Atoms of gold = 2.4 × 10²⁴ atoms

Mass of gold = ?

Solution:

First of all we will convert the number of atoms into moles.

2.4 × 10²⁴ atoms × 1 mol/ 6.02 × 10²³ atoms

number of moles = 3.99 mol

Now we will determine the mass of gold.

Mass = number of moles × molar mass

Mass =  3.99 mol × 196.97 g/mol

Mass = 785.9 g

8 0
3 years ago
Read 2 more answers
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