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Aloiza [94]
3 years ago
6

I will give brainliest!!! What is the density of a sample of chlorine gas that exerts a pressure of 4.5 atm in a 12.6 L containe

r at 36 c (Answer in 4 digits)
Please help I'm so confused!
Chemistry
1 answer:
labwork [276]3 years ago
7 0

Answer : The density of a sample of chlorine gas is, 12.59 g/L

Explanation :

To calculate the density of chlorine gas we are using ideal gas equation.

PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\frac{RT}{M}\\\\P=\frac{\rho RT}{M}

where,

P = pressure of chlorine gas = 4.5 atm

V = volume of chlorine gas = 12.6 L

n = number of moles of chlorine gas

w = mass of chlorine gas

R = gas constant = 0.0821 L.atm/mol.K

T = temperature of chlorine gas = 36^oC=273+36=309K

M = molar mass of chlorine gas = 71 g/mol

Now put all the given values in the above formula, we get:

P=\frac{\rho RT}{M}

4.5atm=\frac{\rho \times (0.0821L.atm/mol.K)\times (309K)}{71g/mol}

\rho=12.59g/L

Therefore, the density of a sample of chlorine gas is, 12.59 g/L

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Answer:

The enthalpy change for the given reaction is 424 kJ.

Explanation:

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We have :

Enthalpy changes of formation of following s:

\Delta H_{f,Cu(NO_3)_2}=-302.9 kJ/mol

\Delta H_{f,CuO}=-157.3 kJ/mol

\Delta H_{f,NO_2}= 33.2 kJ/mol

\Delta H_{f,O_2}= 0 kJ/mol (standard state)

\Delta H_{rxn}=\sum [\Delta H_f(product)]-\sum [\Delta H_f(reactant)]

The equation for the enthalpy change of the given reaction is:

\Delta H_{rxn} =

=(2 mol\times \Delta H_{f,CuO}+4\times \Delta H_{f,NO_2}+1 mol\times \Delta H_{f,O_2})-(2mol\times \Delta H_{f,Cu(NO_3)_2})

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(2mol\times (-157.3 kJ/mol)+4\times 33.2 kJ/mol=1 mol\times 0 kJ/mol)-(2 mol\times (-302.9 kJ/mol)

\Delta H_{rxn}=424 kJ

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6 0
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volume of solute - 16.0 mL
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If 15.0 mL of phosphoric acid completely neutralizes 38.5 mL of 0.150 mol/L calcium hydroxide, what is the concentration of the
Sedbober [7]

Answer:

Let me give it a try.

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Balancing this reaction

2H3PO4 + 3Ca(OH)2 == Ca3(PO4)2 + 6H2O.

Moles= Molarity x Volume

Volume = 38.5ml = 0.0385L

Moles of Ca hydroxide = 0.150m/L x 0.0385L

(Notice the units canceling out...leaving moles).

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From balanced reaction...

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0.005775moles of Ca(OH)2 would completely react with....

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Volume of solution assuming no other additions to the reaction = 15ml + 38.5ml =53.5ml =0.0535L

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If this is wrong

then Simply Try The formula for Mixing of solutions

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2 years ago
(2 x 109) x (5 x 105).
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Answer:

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8 0
2 years ago
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