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Ilia_Sergeevich [38]

3 years ago

14

A dramatic demonstration, called "singing rods," involves a long, slender aluminum rod held in the hand near the rod's midpoint.

the rod is stroked with the other hand. with a little practice, the rod can be made to "sing," or emit a clear, loud, ringing sound.

1 answer:

Korvikt [17]3 years ago

8 0

More vibration = higher frequency

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reviews the approach taken in problems such as this one. A bird watcher meanders through the woods, walking 0.916 km due east, 0

Verizon [17]

Answer:

Displacement: 2.230 km Average velocity: 1.274 $\frac{km}{h}$

Explanation:

Let's represent displacement by the letter S and the displacement in direction 49.7° as A. Displaement is a vector, so we need to decompose all the bird's displacement into their X-Y compoments. Let's go one by one:

0.916 km due east is an horizontal direction and cane be seen as direction towards the negative side of X-axis.

0.928 km due south is a vertical direction and can be seen as a direction towards the negative side of Y-axis.
3.52 km in a direction of 49.7° has components on X and Y axes. It is necessary to break it down using trigonometry,

First of all. We need to sum all the X components and all the Y componets.

∑ $Sx = Ax -0.916$ ⇒ ∑ $Sx = [tex]3.52cos(49.7) - 0.916$

∑ $Sx = 1.361 km$

∑ $Sy = Ay - 0.918$ ⇒ ∑ $Sy = 3.52sin(49.7) - 0.918$

∑ $Sy = 1.767$

The total displacement is calculated using Pythagoeran therorem:

$S_{total} =\sqrt{Sx^{2}+ Sy^{2} }$ ⇒

$S_{total} = 2.230 km$

With displacement calculated, we can find the average speed as follows:

$V = S/t$ ⇒ $V = \frac{2.230}{1.750}$

$V = 1.274\frac{km}{h}$

7 0

2 years ago

A thin walled spherical shell is rolling on a surface. What

ExtremeBDS [4]

Answer:

$=\frac{1/3}{5/6} = 0.4$

Explanation:

Moment of inertia of given shell $= \frac{2}{3} MR^2$

where

M represent sphere mass

R -sphere radius

we know linear speed is given as $v = r\omega$

translational $K.E = \frac{1}{2} mv^2 = \frac{1}{2} m(r\omega)^2$

rotational $K.E = \frac{1}{2} I \omega^2 = \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

total kinetic energy will be

$K.E = \frac{1}{2} m(r\omega)^2 + \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

$K.E =\frac{5}{6} MR^2 \omega^2$

fraction of rotaional to total K.E

$=\frac{1/3}{5/6} = 0.4$

8 0

3 years ago

Bill is learning to play tennis. He does pretty well hitting the ball back to his opponent but, many times he misses the ball wh

KiRa [710]

Answer: Place his feet parallel to the baseline prior to tossing the ball

5 0

2 years ago

NEED HELP ASAPTsunamis are often called tidal waves because they are caused by tides.

garik1379 [7]

Answer:

false

Explanation:

a tsunami is almost always caused by an earthquake under water.

5 0

2 years ago

A ball is traveling 24° above the horizontal at a speed of 12 m/s. What is the vertical component of its speed?

victus00 [196]

Answer:

4.88 m/s

Explanation:

Vertical component would be 12 * sin 24 = 4.88 m/s

Horizontal is 12 * cos 24

3 0

2 years ago