Yes they can.
Don't really know any examples
Answer:
11.306 nm/s
or
113.06 atomic layers/sec
Explanation:
Hello!
First we need to know how much an inch equals in nanometers and a day in seconds:
Since <em>1inch = 2.54cm</em> and <em>1cm=10^7nm</em>
<em> </em>1 inch = 2.54 * 10^7 nm<em> </em>
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Also <em>1day = 24hours = 24*60minutes = 24*60*60seconds</em>
<em> </em>1 day = 86.4 * 10^3 s
Therefore the rate at which the hair grows in nanometers per seconds is:
1/26 in/day = (1/26) * (2.54*10^7)/(86.4*10^3) = 11.306 nm/s
Now, if 1 atomic layer = 0.1 nm this means that 1 nm = 10 atomic layers.
Therefore:
The rate in atomic layers is
11.306 nm/s = 11.306 (10 atomic layers)/s = 113.06 atomic layers/sec
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<span>273 K is the freezing point of water and it is equal to 0 degrees Celcius ,In this change ,heat is released so as to gain the suitable temperature for freezing.273 K is just the Celsius scale but with being 0 but the same scale ,this number was arrived at because temperature comes from the motion of a substance's particles.</span>
Honestly, I am quite confused with what Nv stands for because there is no element with that symbol. However, I still get the concept of finding the average molecular mass of an element. Let's just assume that nv stands for a specific type of element and it has two isotopes: nv-293 and nv-295. Isotopes have the same number of protons but differ in mass number (protons+neutrons).
To find the average atomic weight, just multiply the individual weights with the respective composition of the isotope. Since there are only two isotopes, they constitute 50% each. So, the average atomic weight is
(50%)(293.15 amu) + (50%)(<span>295.30 amu) = 294.225 amu
Hence, the atomic weight of nv is 294.225 atomic mass units.</span>
Radio waves - radio waves have the longest wavelengths of all the electromagnetic waves. they range from around a foot long to several miles long. Radio waves are often used to transmit data and have been used for all sorts of applications including radio, satellites, radar, and computer networks. hope it helps
