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zimovet [89]
3 years ago
5

Reflected light from a thin film of oil gives constructive interference for light with a wavelength inside the film of λfilm. By

how much would the film thickness need to be increased to give destructive interference?
A. 2λfilm   
B. λfilm   
C. λfilm/2   
D. λfilm/4
Physics
1 answer:
My name is Ann [436]3 years ago
3 0

Answer:D. λfilm/4

Explanation: Destructive interference is a type of wave interference which means the coming together or over-lapping of two opposing waves creating No effect or the Cancellation of the wave impact. An example of destructive wave is when Noise cancel the effect of sound from a head phone.

The film thickness will need to be increased by λfilm/4 for it to be able to give a destructive interference.

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Need help asap pls
Zinaida [17]
B. third

for every action there is a reaction*
6 0
2 years ago
1.) if you are sitting still are you accelerating? How do you know?
castortr0y [4]

yes. gravity is working on you and everything on you.

also earth is rotating


no not in respect ofimmediate surroundings

object could move at constant velocity = no change in either magnitude or direction

change of position "proves" this

5 0
3 years ago
A 222 kg bumper car moving right at 3.10 m/s collides with a 165 kg bumper car moving 1.88 m/s left Find the total momentum of t
Svetlanka [38]

Answer:

Total momentum of the system is 378 kg-m/s

Explanation:

It is given that,

Mass of first bumper car, m₁ = 222 kg

Velocity of first bumper car, v₁ = 3.10 m/s (in right)

Mass of other bumper car, m₂ = 165 kg

Velocity of second bumper car, v₂ = -1.88 m/s (in left)

Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :

p=m_1v_1+m_2v_2

p=222\ kg\times 3.10\ m/s+165\ kg\times (-1.88\ m/s)

p = 378 kg-m/s

Hence, the total momentum of the system is 378 kg-m/s

5 0
3 years ago
A 200. Kg load of bricks is to be lifted from the ground to the top of a 30.0 m high building in 30.0 s. If a 75.0 N frictional
coldgirl [10]

Answer:

The minimum power the motor would need is 2035 Watts.

Explanation:

the minimum power motor needed is given by the total work done on the load, Wtot and the total time it takes the load to be lifted, given by:

P = Wtot/t

the forces doing works on the load is the gravitational force, Wfg and the frictional force, Wf the total work done on the load is:

Wtot = Wfg + Wf

        =  m×g×d + f×d

        = d×(m×g + f)

        = (30)×(200×9.8 + 75)

         = 61050 J

it takes t = 30s for the load to be lifted high the building, the minimum power neeed is then:

P = Wtot/t

  = (61050)/(30)

  = 2035 Watts

Therefore, the minimum power the motor would need is 2035 Watts.

3 0
3 years ago
What is the average for the following set of measurements 3.1 mL, 2.7 mL, 4.6 mL, 1.9mL, 8.7 mL
Oksanka [162]
C. 4.2 mL
3.1+2.7+4.6+1.9+8.7mL=21
there are 5 numbers
21÷5=4.2
6 0
3 years ago
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