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zimovet [89]
3 years ago
5

Reflected light from a thin film of oil gives constructive interference for light with a wavelength inside the film of λfilm. By

how much would the film thickness need to be increased to give destructive interference?
A. 2λfilm   
B. λfilm   
C. λfilm/2   
D. λfilm/4
Physics
1 answer:
My name is Ann [436]3 years ago
3 0

Answer:D. λfilm/4

Explanation: Destructive interference is a type of wave interference which means the coming together or over-lapping of two opposing waves creating No effect or the Cancellation of the wave impact. An example of destructive wave is when Noise cancel the effect of sound from a head phone.

The film thickness will need to be increased by λfilm/4 for it to be able to give a destructive interference.

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One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s
DedPeter [7]

Complete Question

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cm across, and you estimate that the distance from the window shade to the wall is about 5 m.

Required:

Estimate the diameter of the pinhole.  

Answer:

The diameter is  d =0.000336 m

Explanation:

     From the question we are told that

            The central maxima is D= 2cm = \frac{2}{100} = 0.02m

            The distance from the window shade is L = 5m

     The  average wavelength of the  sun is mathematically evaluated as

                         \lambda_{ave } = \frac{\lambda_i  + \lambda_f}{2}

 Generally the visible light spectrum  has a wavelength  range  between  400 nm  to 700 nm  

        So  the initial wavelength of the sun is \lambda _i = 400nm

           and the final wavelength is  \lambda_f = 700nm

  Substituting this into the above equation

                 \lambda_{sun} = \frac{400nm  +700nm}{2}

                        = 550nm

The diameter is evaluated as

              d = \frac{2.44 \lambda_{sun} L}{D}

substituting values

              d = \frac{2.44 * 550*10^{-9} * 5 }{0.02}

                d =0.000336 m

5 0
3 years ago
Calculate the potentia energy of a car with a mass of 3800kg that is on a hill 110 meters above sea level? USE 10 instead of 9.8
Arada [10]

Potential energy (PE ) = m g h

Where:

m = mass = 3800 kg

g = acceleration due gravity = 10 m/s^2

h = heigth = 110 meters

Replacing:

PE = 3800 * 10 * 110 = 4,180,000 J

7 0
1 year ago
Displacement vectors of 4 km north, 2km south, 5 km north, and 5km south combine to a total displacement of A 2 km south B 16 km
prohojiy [21]
I would prolly say C. 16 km south.
4 0
3 years ago
Read 2 more answers
A basketball player can leap upward 0.43 m. how long does he remain in the air? use an acceleration due to gravity of 9.80 m/s2
MArishka [77]
From the equations of linear motion,
v² = u² + 2as where v is the final velocity, u is the initial velocity and a is the gravitational acceleration, and s is the displacement,
Thus, v² = u² -2gs, but v=0
hence, u² = 2gs
                = 2×9.81×0.43
                = 8.4366
            u = √8.4366
               =2.905 m/s
Hence the initial velocity is 2.905 m/s
 Then using the equation v= u +gt .
Therefore, v = u -gt. (-g because the player is jumping against the gravity)
but, v = 0
Thus, u= gt
Hence, t = u/g
              = 2.905/9.81
              = 0.296 seconds


3 0
3 years ago
A truck moves 100 miles to the south in 2 hours. What is the trucks velocity
ruslelena [56]

v = d/t

v = 100/2

v=50

50 mph

3 0
3 years ago
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