Answer:
(a) Explained below
(b) ![v_f=0.35\ m/s](https://tex.z-dn.net/?f=v_f%3D0.35%5C%20m%2Fs)
(c) Yes
Explanation:
<u>Law Of Conservation Of Linear Momentum</u>
The total linear momentum of a system of particles or objects is conserved unless an external force is acting on the system. The formula for the momentum of a body with mass m and velocity v is P=mv. If there is a system of bodies, then the total linear momentum is the sum of the individual momentums
![P=m_1v_1+m_2v_2+...+m_nv_n](https://tex.z-dn.net/?f=P%3Dm_1v_1%2Bm_2v_2%2B...%2Bm_nv_n)
When objects collide and join together, the only final mass is the sum of all masses, all traveling at the same speed.
Our
fullback runs at
. Two two 68-kg linebackers attempt to stop him, one at -2.0 m/s and the other at -4.0 m/s. The negative value is because the run against the positive direction, taken in the direction of the fullback.
(a) Before the event, there is a total linear momentum, computed as the sum of the momentums of each player as shown
![p_1=m_1v_1=(98)(5)=490 Kg\ m/s](https://tex.z-dn.net/?f=p_1%3Dm_1v_1%3D%2898%29%285%29%3D490%20Kg%5C%20m%2Fs)
![p_2=m_2v_2=(68)(-4)=-272 kg\ m/s](https://tex.z-dn.net/?f=p_2%3Dm_2v_2%3D%2868%29%28-4%29%3D-272%20kg%5C%20m%2Fs)
![p_3=m_3v_3=(68)(-2)=-136 kg\ m/s](https://tex.z-dn.net/?f=p_3%3Dm_3v_3%3D%2868%29%28-2%29%3D-136%20kg%5C%20m%2Fs)
![p_t=p_1+p_2+p_3=390-272-136=82\ kg\ m/s](https://tex.z-dn.net/?f=p_t%3Dp_1%2Bp_2%2Bp_3%3D390-272-136%3D82%5C%20kg%5C%20m%2Fs)
After the collision, all the players keep joined in one single mass of.
![m_t=98+68+68=234\ kg](https://tex.z-dn.net/?f=m_t%3D98%2B68%2B68%3D234%5C%20kg)
They will move at a speed which will be computed below
(b) The final momentum of the system is
![p_f=m_tv_f=82\ kg\ m/s](https://tex.z-dn.net/?f=p_f%3Dm_tv_f%3D82%5C%20kg%5C%20m%2Fs)
Since the linear momentum is conserved, the final speed
is common to all of the players. Let's solve to find it
![\displaystyle v_f=\frac{p_f}{m_t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v_f%3D%5Cfrac%7Bp_f%7D%7Bm_t%7D)
![\displaystyle v_f=\frac{82}{234}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v_f%3D%5Cfrac%7B82%7D%7B234%7D)
![v_f=0.35\ m/s](https://tex.z-dn.net/?f=v_f%3D0.35%5C%20m%2Fs)
(c) Since the final speed of the players is positive, it means the touchdown was actually scored, the fullback moved forward across the goal line, the positive reference.