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3 years ago

Use V=Voe^-t/RC and T=RC to derive T1/2=Tln2

Physics

1 answer:

Ksju [112]3 years ago

3 0

Enclosed is some guidance algebra.I find this q a little confusing. It quotes "RC" which usually makes me think of electrical circuits and time constants based on converting calculating RC value and equating that to t for one time constant then 2RC for two time constants etc. The theory being that after 5 time constants - 5RC - a circuit is stable. BUT, this q then goes on to mention HALF LIFE. The curves for both half life and time constant are both exponential, as in the number e to the power of something, but the algebra is slightly different. I hope my algebra is ok.

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a football player initially at rest accelerates uniformly as she runs down the field, travelling 17m (E) in 3.8s. What is her fi

ikadub [295]

X - Xo = 0.5(Vo +V)t

Xo cancels because it is 0 (she is at rest)

17 = 0.5(0+V)3.8

17 = 1.9V

Final velocity is 8.94737 m/s

6 0

3 years ago

A hot air balloon is filled with 1.45 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 109 ∘ C . Wha

just olya [345]

Answer:

The volume of air after the balloon is heated = 1.95 × 10⁶ L

Explanation:

Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.

It can be expressed mathematically as,

V₁/T₁ = V₂/T₂

Making V₂ The subject of the equation

V₂ = (V₁/T₁)T₂.................... Equation 1

Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature

Given: V₁ = 1.45 × 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.

Substituting these values into equation 1 above,

V₂ = (1.45×10⁶)382/284

V₂ = 1.95 × 10⁶ L

Therefore the volume of air after the balloon is heated = 1.95 × 10⁶ L

6 0

3 years ago

A 481-m long spaceship passes by an observer at the speed of 2.70×10^8 m/s. What length does the observer measure for the spaces

galben [10]

Answer:

209.66 m

Explanation:

Given:

Original length of the spaceship, L = 481 m

Speed of the spaceship, v = 2.70 × 10⁸ m/s

Now,

using the concept of length contraction, we have

$L=\frac{L'}{\sqrt{1-\frac{v^2}{c^2}}}$

where,

L' is the observed length

c is the speed of the light

Thus,

on substituting the respective values, we get

$481=\frac{L'}{\sqrt{1-\frac{(2.70\times10^8)^2}{(3\times10^8)^2}}}$

L' = 209.66 m

3 0

4 years ago

What is the difference between an atom in the ground state and an atom in an excited state

SIZIF [17.4K]

The atom in an excited state has more energy and is less stable than the atom in the ground state.

7 0

4 years ago

Read 2 more answers

•What power does a pump develop to lift 35 L of water per minute

guajiro [1.7K]

Answer:

$p = \frac{w}{t} \\ p = \frac{f \times d}{t} \\ p = \frac{m \times g \times d}{t} \\ p = \frac{35 \times 9.8 \times 110}{60.0} \\ p = 629w$

8 0

3 years ago