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3 years ago

Can you do all questions

Physics

1 answer:

faust18 [17]3 years ago

3 0

Answer:

this is for help not answer so I'm sorry I can not do all the answers but can help if you need it

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A small box slides down a ramp on a friction with surface. If the total energy of the system is conserved, which computational m

spayn [35]

Answer:

WWWEEEEEEEEEEEEEEEEEE

Explanation:

6 0

3 years ago

Read 2 more answers

Is mechanical advantage always greater than one?

oee [108]

No, it can also be less than 1 depending on the class of the lever.

6 0

3 years ago

A crate of eggs is located in the middle of the flatbed of a pickup truck as the truck negotiates a curve in the flat road. The

oksian1 [2.3K]

Answer:

v = 14.35 m/s

Explanation:

As we know that crate is placed on rough bed

so here when pickup will take a turn around a circle then in that case the friction force on the crate will provide the necessary centripetal force on the crate

So here we have

$\mu mg = \frac{mv^2}{R}$

here we have

$\mu g = \frac{v^2}{R}$

now we know that

$v = \sqrt{\mu Rg}$

here we have

$\mu = 0.600$

R = 35 m

g = 9.81 m/s/s

now plug in all values in above equation

$v = \sqrt{(0.600)(35)(9.81)}$

$v = 14.35 m/s$

4 0

3 years ago

What will happen and give a reason

djyliett [7]

Answer:

1 or 2 or 3

Explanation:

it depends whether the coat is a light or dark colour. if it is lighly coloured it will not absorb heat from the sun and wont melt the snowman. if it is darkly coloured it will be number 1

the coat wont make a difference if the temperature of the snowman is the same and the temperature outside the snoman and the sun isnt shining. the coat would just make him look smart - so number 2

it coul keep in the cold and block out the warmth so number 3

4 0

4 years ago

A 75 kg football player is gliding forward across very smooth ice at 4.6 m/s. He throws a 0.47 kg football straight forward. A)

lord [1]

Answer:

4.53482 m/s

4.506 m/s

Explanation:

$m_1$ = Mass of player = 75 kg

$v_1$ = Initial velocity of player = 4.6 m/s

$m_2$ = Mass of ball = 0.47 kg

$v_1$ = Initial velocity of ball = 15 m/s

The linear momentum of the system is conserved

$(m_1+m_2)v_1=m_1v+m_2v_2\\\Rightarrow v=\dfrac{(m_1+m_2)v_1-m_2v_2}{m_1}\\\Rightarrow v=\dfrac{(75+0.47)4.6-0.47\times 15}{75}\\\Rightarrow v=4.53482\ m/s$

The player's speed is 4.53482 m/s

In the second case the equation of momentum is

$(m_1+m_2)v_1=m_1v+m_2(v_2+v_1)\\\Rightarrow v=\dfrac{(m_1+m_2)v_1-m_2(v_2+v_1)}{m_1}\\\Rightarrow v=\dfrac{(75+0.47)4.6-0.47\times (15+4.6)}{75}\\\Rightarrow v=4.506\ m/s$

The player's speed is 4.506 m/s

4 0

4 years ago