Plz, Help I just need this question to be answered so I can be done with this worksheet.
1 answer:
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Answer:
"Apparent weight during the "plan's turn" is 519.4 N
Explanation:
The "plane’s altitude" is not so important, but the fact that it is constant tells us that the plane moves in a "horizontal plane" and its "normal acceleration" is
Given that,
v = 420 m/s
R = 11000 m
Substitute the values in the above equation,
It has a horizontal direction. Furthermore, constant speed implies zero tangential acceleration, hence vector a = vector a N. The "apparent weight" of the pilot adds his "true weight" "m" "vector" "g" and the "inertial force""-m" vector a due to plane’s acceleration, vector
In magnitude,
Because vector “a” is horizontal while vector g is vertical. Consequently, the pilot’s apparent weight is vector
Which is quite heavier than his/her true weigh of 519.4 N
Answer:
a)
b)
Explanation:
Given:
mass of the ball,
horizontal velocity of the ball,
mass of the person,
a)
<u>Using the law of conservation of momentum:</u>
b)
Given:
- rebound velocity of the ball,
Using conservation of momentum,