Magnesium iodide = MgI₂
mass of Mg = 24.3g
mass of I = 126.9g
mass of MgI₂ = 24.3 + 2*126.9 = 278.1g = 1 mole
in 5.36x10⁻⁴ mole of MgI₂ ---------------- x g of Mg
in 1 mole of MgI₂ ------------------------------ 1 mole of Mg
x = 5.36x10⁻⁴ moles of Mg = 0.000536 moles of Mg
answer: we've 0.000536 moles of Mg (magnesium ions) in 5.36x10⁻⁴ moles of MgI₂
the ideal gas equation is PV=nRT
where P=pressure
V=Volume
n=no. of moles
R=universal gas constant
T=temperature
The universal gas constant (R) is 0.0821 L*atm/mol*K
a pressure of 746 mmhg =0.98 atm= 1 atm (approx)
T=37 degrees Celsius =37+273=310 K (convert it to Kelvin by adding 273)
V=0.7 L (only getting oxygen, get 21% of 3.3L)
Solution:
(1 atm)(0.7 L)=n(0.0821 L*atm/mol*K)(310 K)
0.7 L*atm=n(25.451 L*atm/mol)
n=0.0275 mole
Answer:
n=0.0275 mole of oxygen in the lungs.
It is the independent variable because you can ‘manipulate’ or ‘change’ it.
Answer:
illustrates ways things are similar and different
Explanation:
Answer:
Solubility, length, hardness, color, mass, density, weight, volume, boiling, and point.
Explanation: Hope this helps
