Answer:
Fluorine has the atomic number which contain protons and electrons. ... As the number of electrons is increased, the nuclear force of attraction is decreased. Thus, the radius of fluoride ions is larger than that of fluorine atoms.
Explanation:
Answer:
2:1
1.2 × 10² g
Explanation:
Step 1: Write the balanced combustion equation
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to CH₄ is 2:1.
Step 3: Calculate the moles of CH₄ required to react with 15 moles of O₂
We will use the previously established molar ratio.
15 mol O₂ 1 mol CH₄/2 mol O₂ = 7.5 mol CH₄
Step 4: Calculate the mass corresponding to 7.5 moles of CH₄
The molar mass of CH₄ is 16.04 g/mol.
7.5 mol × 16.04 g/mol = 1.2 × 10² g
Molar mass
Ca₃(PO₄)₂ = 310 g/mol
1 mole -------------------> 310 g
2.3x10⁻⁴ mole ---------> ?
m = 2.3x10⁻⁴ * 310 / 1
m = 0.0713 g
hope this helps!
The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.
<u>Given the following data:</u>
- Quantity of energy = 400 Joules
- Initial temperature = 20°C
To determine the specific heat capacity of this chunk of metal:
<h3>
The formula for quantity of heat.</h3>
Mathematically, quantity of heat is given by the formula;

<u>Where:</u>
- Q represents the quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity.
- ∅ represents the change in temperature.
Making c the subject of formula, we have:

Substituting the given parameters into the formula, we have;

Specific heat, c = 0.32 J/g°C.
Read more on specific heat here: brainly.com/question/2834175
Answer:
237.2 mL.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
(XMV) acid = (XMV) base.
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
<em>(XMV) HCl = (XMV) NaOH.</em>
<em></em>
For HCl; X = 1, M = 0.5 M, V = ??? mL.
For NaOH, X = 1, M = 1.54 M, V = 77.0 mL.
<em>∴ V of HCl = (XMV) NaOH / (XV) HCl = (</em>1)(1.54 M)(77.0 mL) / (1)(0.5 M) = <em>237.2 mL.</em>