Option B: 2, 8, 18, 32.
2 in the K shell, 8 in L shell, 18 in M shell and 32 in N shell.
Answer:
Final temperature = T₂ = 328.815 K
Explanation:
Given data:
Given energy = 980 KJ = 980×1000= 980000 J
Volume = 6.2 L
Initial temperature =T₁= 291 K
Specific heat of water = 4.18 j /g .K
Final temperature = T₂ = ?
Formula:
Q = m. c . ΔT
ΔT = T₂ - T₁
we will first convert the litter into milliliter
6.2 × 1000 = 6200 mL
It is given in question that
1 mL = 1 g
6200 mL = 6200 g
Now we will put the values in formula,
Q = m. c . (T₂ - T₁)
980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)
980000 j = 25916 j/ k . (T₂ - 291 K)
980000 j / 25916 j/ k = T₂ - 291 K
37.8145 K + 291 K =T₂
T₂ = 328.815 K
2 Ionic bonds form between metal atoms and nonmetal atoms.
4 The less electronegative atoms transfers one or more electrons to the more electronegative atom.
5 The metal atom forms a cation and the nonmetal atom forms an anion.
7 The attraction between ions with an opposite charge forms an ionic bond.
Answer:
diiodomethane
Explanation:
The densities of each of the liquids mentioned in the question are stated below;
CCl4- 1.59 g/cm^3
Hexane- 0.672 g/cm^3
Benzene- 0.8765 g/cm^3
Diiodomethane- 3.3 g/cm^3
Clearly, the density of diiodomethane methane is almost the same as that of the desired granular material, hence the undesired granular material having a density of 2.04 g/cm3 will float in diiodomethane thus separating the two granular materials.
