The equivalent capacitance of this circuit is = 21F. That is option A.
<h3>Calculation of the equivalent capacitance</h3>
When capacitors are connected together in parallel the total or equivalent capacitance, CT in the circuit is equal to the sum of all the individual capacitors added together.
The four capacitors are 10 F, 3 F, 7 F, and 1 F.
Therefore the equivalent capacitance = 10 + 3 + 7 + 1=21F
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d(t) = 1.1t² + t + 1
The constant speed required to cover the same distance between t = 3 to t = 5 is the same as the average speed over that same time interval. It is given by:
v = Δx/Δt
v = average speed, Δx = change in distance, Δt = elapsed time
Given values:
Δx = d(5) - d(3) = 19.6ft
Δt = 5s - 3s = 2s
Plug in and solve for v:
v = 19.6/2
v = 9.8ft/s
Answer:
41.2 m.
Explanation:
It takes half the time that is (5.8/2) = 2.9 seconds, for the ball to reach its apex.
Given:
S = 83 m
t = 5.8 s
vf = 0 m/s
a = - g
= - 9.81 m/s^2
Equations of motion:
i. vf = vi + a * t
ii. h = vi * t + 1/2 (a * t²)
Using the i. equation of motion:
0 m/s = vi - (9.8 m/s²) (2.9 sec)
vi = 28.4 m/s.
Using the ii. equation of motion:
h = (28.4 * 2.9 ) - 1/2 (9.8 * (2.9)²)
= 82.4 - 41.2
= 41.2 m.
Answer:
the power that must be supplied to the motor is 101.45 hp
Explanation:
Given that,
The weight of elevator = 1000lb
The motor exerts a constant force of 500 lb on the cable
The load has been hoisted s = 15 ft starting from rest
The motor has an efficiency of e = 0.65
According to the equation of motion:
F = ma
To calculate the output power:
P(out) = F. v
P(out) = 3 (500) * 21.98
P(out) = 32970 lb.ft/s
As efficiency is given and output power is known, we can calculate the input power.
ε = P(out) / P(in)
0.65 = 32970 / P(in
)
P(in) = 50,723 lb.ft/s
P(in) = 50,723 / 500 hp
= 101.45 hp
the power that must be supplied to the motor is 101.45 hp
Answi am sorry but i do not know the answer
Explanation:
