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snow_tiger [21]
2 years ago
7

A change that produces one or more new substances is called _____.

Physics
2 answers:
natali 33 [55]2 years ago
5 0
A change in matter that produces one or more new substances is a chemical change, or chemical reaction. In a chemical change, atoms rearrange to form new substances, which results in different physical properties, as well.
Citrus2011 [14]2 years ago
3 0

Answer:

A change that produces one or more new substances is called

<u>a chemical change</u><u>.</u>

<u></u>

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Consider a snooker ball, with a mass of 0.07kg, rolling along a table at a speed of 4.1m/s. It hits a side cushion of the snooke
zavuch27 [327]

Answer: - 3.4 \times 10^{-3} N

Explanation:

From Newton's law of motion, Force is equal to rate of change of momentum.

The initial velocity of the ball, u = 4.1 m/s

mass of the ball, m = 0.07 kg

During contact, velocity = 0

Time of contact, t = 72 ms = 72 × 10⁻³ s

F = \frac{m(v-u)}{t} = \frac{0.07 kg \times (0-4.1 m/s)}{72 \times 10^{-3}s} = - 3.4 \times10^{-3} N

Thus, net force applied to the ball during this collision is - 3.4 \times 10^{-3} N

4 0
3 years ago
As the mass and volume increases, the densit will<br> Increase, decrease, or remain the same
ikadub [295]
We can't tell from the information given.

Density is the RATIO of mass to volume.  So, if mass and volume both
increase but their ratio decreases, then the density decreases.

But if mass and volume both increase and their ratio also increases,
then the density increases.

Examples:

-- Start with a pile of some kind of substance.
    Mass = 150 grams
    Volume = 100 cm³

    Density = (mass) / (volume) = (150 gm)/(100cm³)  =  1.5 gm/cm³

-- Add 50 grams of mass.  Mass = 200 gm.
    Add 50 cm³ of volume.  Volume = 150cm³.

     Density = (mass) / (volume) = (200 gm)/(150 cm³)  =  1.33 gm/cm³.
                                                                                  Density decreased.

-- To the original pile, add 100 grams of mass.  Mass = 250 gm.
                               add 50 cm³ of volume.  Volume= 150 cm³.

     Density = (mass) / (volume) = (250 gm)/(150 cm³)  =  1.67 gm/cm³.
                                                                            Density increased.

-- To the original pile, add 60 grams of mass.  Mass = 210 gm.
                               add 40 cm³ of volume.  Volume = 140 cm³.

   Density = (mass) / (volume) = (210 gm)/(140 cm³)  =  1.5 gm/cm³.
                                                                         Density no change.
                                                                 Same as the original pile.
6 0
3 years ago
you can use a torque feeler that consists of a meterstick held at the 0 cm end with a weight dangling from various positions alo
Deffense [45]

Answer:

T=7.3575\ N.m

Explanation:

Given:

length of the stick, l=100\ cm=1\ m

position of holding the stick that acts as a hinge, f=0\ cm

mass of the object, m=1\ kg

position of hanging the mass on the meter stick, x=50\ cm=0.5\ m

new position of hanging the mass, x'=75\ cm=0.75\ m

<u>Now the torque in the initial position:</u>

T=mg.x

where:

g= acceleration due to gravity

T=1\times 9.81\times 0.5

T=4.905\ N.m

Now when the mass is at the new position:

T=mg.x'

T=1\times 9.81\times 0.75

T=7.3575\ N.m

7 0
3 years ago
A mixture of 5 cm3 of CH4 and 100 cm3 of air is exploded. Assume air is 80% N2 by volume and 20% O2 by volume. The resulting mix
Zinaida [17]

Answer:

The composition of the resulting gas;

A. 5 cm³ of CO₂, 10 cm³ of O₂, 80 cm³ of N₂, and 10 cm³

Explanation:

The given parameters are;

The volume of CH₄ in the mixture of air and methane = 5 cm³

The volume of air in the mixture of air and methane = 100 cm³

The percentage by volume of nitrogen, N₂ in the air = 80%

The percentage by volume of oxygen, O₂ in the air = 20%

The equation for the reaction of the chemical reaction between the methane and the air in the mixture is given as follows;

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)

Therefore, we have;

1 mole of CH₄ reacts with 2 moles of O₂ to produce 1 mole of CO₂ and 2 moles of H₂O

By Avogadro's law, we have that equal volumes of all gases at the same temperature and pressure contains equal number of molecules

Therefore, we have;

1 cm₃ of CH₄ reacts with 2 cm³ of O₂ to produce 1 cm³ of CO₂ and 2 cm³ of H₂O

From which we have;

5 cm₃ of CH₄ reacts with 10 cm³ of O₂ to produce 5 cm³ of CO₂ and 10 cm³ of H₂O (steam)

The volume of the oxygen used in the reaction = 10 cm³

The volume of oxygen present in the air = 20% × 100 cm³ = 20 cm³

The volume of nitrogen present in the air = 80% × 100 cm³ = 80 cm³

Therefore, the composition of the resulting gas is given as follows;

1) 80 cm³ Nitrogen

2) 10 cm³ Oxygen

3) 5 cm³ CO₂

4) 10 cm³ H₂O

3 0
2 years ago
If an atom contains 11 protons in its nucleus, predict the element with the atomic number and electronic configuration. Will the
wel
The element is sodium. Atomic number is 11. Electron configuration is 2e- 8e- 1e-. Depends what reaction, because in a sodium and chloride reaction sodium loses 1 electron. Hope this helps
8 0
3 years ago
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