Answer:
The discharge rate is ![Q = 0.0192 \ m^3 /s](https://tex.z-dn.net/?f=Q%20%3D%200.0192%20%5C%20%20m%5E3%20%2Fs)
Explanation:
From the question we are told that
The diameter is ![d = 60 \ mm = 0.06 \ m](https://tex.z-dn.net/?f=d%20%3D%20%2060%20%5C%20mm%20%20%20%3D%20%200.06%20%5C%20m)
The head is ![h = 6 \ m](https://tex.z-dn.net/?f=h%20%20%3D%20%206%20%5C%20m)
The coefficient of contraction is ![Cc = 0.68](https://tex.z-dn.net/?f=Cc%20%20%3D%20%200.68)
The coefficient of velocity is ![Cv = 0.92](https://tex.z-dn.net/?f=Cv%20%20%3D%20%200.92)
The radius is mathematically evaluated as
![r = \frac{d}{2}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Cfrac%7Bd%7D%7B2%7D)
substituting values
![r = \frac{ 0.06 }{2}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Cfrac%7B%200.06%20%7D%7B2%7D)
![r = 0.03 \ m](https://tex.z-dn.net/?f=r%20%3D%20%200.03%20%5C%20m)
The area is mathematically represented as
![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cpi%20r%5E2)
substituting values
![A = 3.142 * (0.03)^2](https://tex.z-dn.net/?f=A%20%3D%20%203.142%20%2A%20%20%280.03%29%5E2)
![A = 0.00283 \ m^2](https://tex.z-dn.net/?f=A%20%3D%200.00283%20%5C%20m%5E2)
The discharge rate is mathematically represented as
![Q = Cv *Cc * A * \sqrt{ 2 * g * h}](https://tex.z-dn.net/?f=Q%20%3D%20%20Cv%20%2ACc%20%20%2A%20%20A%20%20%2A%20%20%5Csqrt%7B%202%20%2A%20g%20%2A%20%20h%7D)
substituting values
![Q = 0.68 * 0.92* 0.00283 * \sqrt{ 2 * 9.8 * 6}](https://tex.z-dn.net/?f=Q%20%3D%200.68%20%2A%20%200.92%2A%20%20%200.00283%20%20%2A%20%20%5Csqrt%7B%202%20%2A%209.8%20%2A%20%206%7D)
![Q = 0.0192 \ m^3 /s](https://tex.z-dn.net/?f=Q%20%3D%200.0192%20%5C%20%20m%5E3%20%2Fs)
Answer:
160 m
Explanation:
The intensity, I, of the sound is inversely proportional to the square of the distance, r, from the source.
![I\propto \dfrac{1}{r^2}](https://tex.z-dn.net/?f=I%5Cpropto%20%5Cdfrac%7B1%7D%7Br%5E2%7D)
Hence,
![I_1r_1^2 = I_2r_2^2](https://tex.z-dn.net/?f=I_1r_1%5E2%20%3D%20I_2r_2%5E2)
![r_2 = r_1\sqrt{\dfrac{I_1}{I_2}}](https://tex.z-dn.net/?f=r_2%20%3D%20r_1%5Csqrt%7B%5Cdfrac%7BI_1%7D%7BI_2%7D%7D)
From the question,
is half of ![I_1](https://tex.z-dn.net/?f=I_1)
![r_2 = r_1\sqrt{\dfrac{I_1}{0.5I_1}}](https://tex.z-dn.net/?f=r_2%20%3D%20r_1%5Csqrt%7B%5Cdfrac%7BI_1%7D%7B0.5I_1%7D%7D)
![r_2 = r_1\sqrt{2}](https://tex.z-dn.net/?f=r_2%20%3D%20r_1%5Csqrt%7B2%7D)
![r_2 = 113\text{ m}\sqrt{2} = 160 \text{ m}](https://tex.z-dn.net/?f=r_2%20%3D%20113%5Ctext%7B%20m%7D%5Csqrt%7B2%7D%20%3D%20160%20%5Ctext%7B%20m%7D)
Firstly, we need to make the times and distance equal to compare.
1hr=60mins
Gonz drove 90km in 60mins,so they would drive 45km in 30 mins dividing it by 2.
Because the Rivs had gone 30km in 30mins, Gonz were faster.
For the adverage speed, we should first add the speed of each family in mph , so 90+60, which equals 150 and divide that by 2 because there are 2 speeds so the average speed is 75mph.
P.S English is my second language so tell me if you don't understand something and I will try and explain.
Answer:
Turn the heater on
Explanation:
There are two main forces involved in a balloon flight
The downward force is the total weight of the balloon: the air it contains, the gas bag, the basket, the passengers, etc.
The upward force is the weight of the of the air the balloon displaces.
During level flight
,
buoyant force = weight of displaced air - total weight of balloon
If you increase the temperature of the air in the bag, the air molecules spread out and leave through the bottom of the bag.
The balloon still has the same volume, so the weight of displaced outside air stays the same.
However, the balloon has lost some hot inside air, so its total weight decreases.
The upward force is greater than the downward force, so the balloon rises.
You first find the mass and the volume of that object. Then you divide mass ÷ volume