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frosja888 [35]
2 years ago
11

Identify the law, write the equation and calculate the answer to the problem below.

Physics
1 answer:
lyudmila [28]2 years ago
5 0

Find refractive index first

\\ \rm\Rrightarrow \mu=\dfrac{c}{v}

\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}

\\ \rm\Rrightarrow \mu =0.75

Now

\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu

\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75

\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr

\\ \rm\Rrightarrow sinr=0.94

\\ \rm\Rrightarrow r=sin^{-1}(0.94)

\\ \rm\Rrightarrow r=70^{\circ}

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
PtichkaEL [24]

This is True

Kinetic energy is the energy of motion. The bicyclist is in motion as he pedals up the tall hill. Therefore, the bicyclist contains kinetic energy.

4 0
3 years ago
Read 2 more answers
Two point charges, initially 2.0 cm apart, experience a 1.0 N force. If they are moved to a new separation of 0.25 cm, what is t
den301095 [7]

Explanation:

Th electric force between charges is inversely proportional to the square of distance between them. It means,

F\propto \dfrac{1}{r^2}

Initial distance, r₁ = 2 cm

Final distance, r₂ = 0.25 cm

Initial force, F₁ = 1 N    

We need to find the electric force between charges if the new separation of 0.25 cm. So,

\dfrac{F_1}{F_2}=(\dfrac{r_2}{r_1})^2\\\\F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{1\times 2^2}{(0.25)^2}\\\\F_2=64\ N

So, the new force is 64 N if the separation between charges is 64 N.

7 0
3 years ago
A magnet’s force is more powerful at its _____
Oliga [24]

Answer:

Explanation: The field of a magnet is strongest at either pole of the magnet. it's equally strong at the North Pole when put next with the South Pole. The force is weaker within the middle of the magnet and halfway between the pole and also the center.

6 0
3 years ago
Bill and Ted are standing on a bridge 40 ft above a river. Bill drops a stone, while Ted decides to throw a stone downward at 10
USPshnik [31]

Answer:

D.

Explanation:

In order to know how long after Bill released his rock should Ted throw his if they want the stones to hit the water simultanously, we need to calculate the time needed to hit the water to both rocks independent each other, and just take the difference.

For the rock dropped by Bill, as the only influence on it is gravity (accelerating it downwards with an acceleration equal to g), and v₀ =0, we can use the following kinematic equation:

y = \frac{1}{2} * g * t^{2}

where y = height = 40 ft.

As all the parameters are given in SI units, it is  advisable to convert this value to m, as follows:

y = 40 ft*\frac{0.3048m}{1 ft} = 12.2 m

Now, we can solve for t, as follows:

t = \sqrt{\frac{2*y}{g}} =  \sqrt{\frac{2*12.2m}{9.8m/s2}} = 1.58 s

For the rock thrown down at 10 m/s, the kinematic equation we just have used becomes:

y = v0*t +\frac{1}{2} * g * t^{2}

This leaves us a quadratic equation on t, as follows:

t = \frac{-10m/s}{9.8m/s2} +/- \sqrt{10m/s^{2} -4*4.9m/s2*(-12.2m)} = -1.02 s +/- 1.88s

Taking the positive root, we have:

t = -1.02 s + 1.88 s = 0.86 s

So, in order to get that both rocks hit the water at the same time, Ted will need to wait the difference between both times:

Δt = 0.86 s - 1.58s = -0.72 s

5 0
3 years ago
Saki is ice-staking to the left with velocity of 5 m/s. A steady breeze starts blowing. Causing saki to accelerate leftward at a
Pavlova-9 [17]

Answer:

Final velocity will be equal to 14 m/sec      

Explanation:

We have given initial velocity u = 5 m/sec

Constant acceleration is given a=1.5m/sec^2

Time t = 6 sec

We have to find the final velocity

From first equation of motion v=u+at, here v is final velocity, u is initial velocity , a is acceleration and t is time

So v=5+1.5\times 6=14m/sec

So equal final velocity will be equal to 14 m/sec

4 0
3 years ago
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