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frosja888 [35]
2 years ago
11

Identify the law, write the equation and calculate the answer to the problem below.

Physics
1 answer:
lyudmila [28]2 years ago
5 0

Find refractive index first

\\ \rm\Rrightarrow \mu=\dfrac{c}{v}

\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}

\\ \rm\Rrightarrow \mu =0.75

Now

\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu

\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75

\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr

\\ \rm\Rrightarrow sinr=0.94

\\ \rm\Rrightarrow r=sin^{-1}(0.94)

\\ \rm\Rrightarrow r=70^{\circ}

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The diameter of a copper wire is thought to be approximately 0.3mm. Which instrument should be used to obtain a more accurate me
erica [24]

Answer:

C

Explanation:

The correct answer should be the micrometer.

<u>The micrometer is an instrument that is capable of measuring the component of an object to very high precision. It is used to obtain accurate measurements in engineering.</u>

<em>In the case of the copper wire, the diameter of 0.3 mm was an approximation and a more accurate measure of the diameter would be obtained by using the micrometer.</em>

The correct option is C.

4 0
3 years ago
Use F = 1/T as your basis:
Varvara68 [4.7K]
  • Time=T=8×10^-5s

Now

\\ \rm\rightarrowtail \nu=\dfrac{1}{T}

\\ \rm\rightarrowtail \nu=\dfrac{1}{8\times 10^{-5}}

\\ \rm\rightarrowtail \nu=0.125(10^5)

\\ \rm\rightarrowtail \nu=12500s^{-1}

\\ \rm\rightarrowtail \nu=12500Hz

6 0
3 years ago
A slide whistle is an open-closed tube with an adjustable plunger that changes the length. You are playing the slide whistle and
Serjik [45]

Answer:

df / ft = -n 12          n= 1, 3, 5, ...

Explanation:

The speed of sound is

         v = λ f

         

In a whistle that we approach by an open tube at one end and closed at the other, standing waves occur, which has a node in the closed part and a maximum in the open pate, whereby wavelength and the distance of the tube are related, the fundamental wave is

         λ₁ = 4L

   The harmonics are

        λ₃ = 4L / 3

        λ₅ = 4L / 5

The general formula

       λₙ = 4L / n              

with n = 1, 3, 5,…

We substitute and clear in the first equation

           f = v n / 4L                        n = 1, 3, 5,…

Let's use derivatives to find the frequency change

           df / dt = v n /4  dL⁻¹ / dt

          d / dt (1/L) = - 1 / L² dL / dt

Where dL / dt = 8 cm / s

We replace

         df / dt = - n v / L2 dL / dt

Let's calculate

         df / dt = - n 340/152 8

         df / ft = -n 12          n= 1, 3, 5, ...

4 0
3 years ago
A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min. How far does the car travel whil
Vesna [10]

Explanation:

<u>Using Equations of Motion</u> :

(1) v = u + at

24 = 6.5 + a * 210

<u>a (Acceleration) = 0.083 m/s^2 </u>

<u>(</u><u>2</u><u>)</u><u> </u> v^2 = u^2 + 2aS

S = 576 - 42.25 / 0.166

<u>S (Distance travelled) = 3215.3 m </u>

(Option A seems a typo since the answer is 3215.3 m)

4 0
3 years ago
Lab: Motion with Constant Acceleration Assignment: Lab Report
matrenka [14]

Answer

3

Explanation:

x=v_{0}<em>t + 1/2 </em>at^{2}<em />

3 0
3 years ago
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