<u>Answer:</u> The value of 
for the given reaction is 0.224
<u>Explanation:</u>
For the given chemical equation:
The expression of for given equation follows:
![K_c=\frac{[H_2][I_2]}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
We are given:
![[HI]_{eq}=0.85M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.85M)
![[H_2]_{eq}=0.27M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D0.27M)
![[I_2]_{eq}=0.60M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D0.60M)
Putting values in above expression, we get:
Hence, the value of for the given reaction is 0.224
Answer:
K2CO3(aq) + H2O(l)
Explanation:
Balance the equation
2KOH(aq) + CO2(g) ------ K2CO3(aq) + H2O(l)
Answer:
+1, lose, 1, 4s, 4s and 3d
Explanation:
<em>An element with the valence electron configuration 4s¹ would form a monatomic ion with a charge of </em><em>+1</em><em>. In order to form this ion, the element will </em><em>lose</em><em> </em><em>1 </em><em>electron from the </em><em>4s </em><em>subshell.</em>
The corresponding oxidation reaction is:
K ⇒ K¹⁺ + 1 e⁻
[Ar] 4s¹ ⇒ [Ar]
<em>If an element with the valence configuration 4s² 3d⁶ loses 3 electrons, these electrons would be removed from the </em><em>4s and 3d</em><em> subshell(s).</em>
The corresponding oxidation reaction is:
Fe ⇒ Fe³⁺ + 3 e⁻
[Ar] 4s² 3d⁶ ⇒ [Ar] 4s⁰ 3d⁵
Non polar molecule have no partial charge ....so non polar answer !!!
