The total atomic number must be the same on each side. The total mass number must be the same on both side.
<span>On the RHS, for the mass number, we have 257 + 4 = 261 (the 4 comes from the 4 neutrons). That means the mass number of the missing piece on the LHS is 261 - 247 = 14. </span>
<span>One the RHS, for the atomic number we have a total of 104 since the 4 neutrons are all neutral. On the LHS, we have this: 104 - 98 = 6. </span>
<span>The missing piece is a nucleus of carbon 14. Done in your style, it is 14/6C</span>
Chemistry msg for 78 mgSO 5.4 answer is NH3
Answer:
a): not necessarily due to London Dispersion Forces and dipole-dipole interactions.
b): not necessarily due to London Dispersion Forces.
Explanation:
There are three major types of intermolecular interaction:
- Hydrogen bonding between molecules with H-O, H-N, or H-F bonds and molecules with lone pairs.
- Dipole-dipole interactions between all molecules.
- London dispersion forces between all molecules.
The melting point of a substance is a result of all three forces, combined.
Note that the more electrons in each molecule, the stronger the London Dispersion Force. Generally, that means the more atoms in each molecule, the stronger the London dispersion force. The strength of London dispersion force between large molecules can be surprisingly strong.
For example, 
(water) molecules are capable of hydrogen bonding. The melting point of at 
is around 
. That's considerably high when compared to other three-atom molecules.
In comparison, the higher alkane hexadecane (
, straight-chain) isn't capable of hydrogen bonding. However, under a similar pressure, hexadecane melts at around 
above the melting point of water. The reason is that with such a large number of atoms (and hence electrons) per molecule, the London dispersion force between hexadecane molecules could well be stronger than that the hydrogen bonding between water molecules.
Similarly, the dipole moments in HCl (due to the highly-polar H-Cl bonds) are much stronger than those in hexadecane (due to the C-H bonds.) However, the boiling point of hexadecane under standard conditions is much higher (at around 
than that of HCl.
Answer:
29.9 g of CO₂ will be produced by the reaction.
Explanation:
This is the reaction:
CaCO₃(s) + 2HCl (aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)
First of all, we state the moles of each reactant:
68.1 g . 1mol/ 100.08g = 0.680 mol of carbonate
51.6 g . 1 mol/36.45g = 1.46 mol of acid.
The solid salt is the limiting reactant. Ratio is 2:1
2 moles of acid can react to 1 mol of salt
1.46 mol of acid may react with (1.46 . 1)/2 = 0.727 moles
As we only have 0.680 moles of salt, we do not have enough.
Let's work at the product side. Ratio is 1:1
1 mo of salt can produce 1 mol of gas
0.680 moles will produce 0.680 moles of gas
We convert the moles to mass → 0.680 mol . 44g / 1mol = 29.9 g of CO₂
To find moles from grams divide the number of moles by the molar mass...
32.7g/18.01 which is 1.82 using significant figure rules
