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ira [324]
3 years ago
9

Zinc is more active than cobalt and iron but less active than aluminum. Cobalt is more active than nickel but less active than i

ron. Which of the following correctly lists the elements in order of increasing activity?
a) Zn < Al < Co < Ni < Feb) Co < Ni < Fe < Zn < Alc) Fe < Ni < Co < Al < Znd) Ni < Co < Fe < Zn < Ale) Ni < Fe < Co < Zn < Al
Chemistry
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

d) Ni < Co < Fe < Zn < Al

Explanation:

electronegativity of Aluminium  1.6

electronegativity of Zinc  1.7

electronegativity of iron  1. 83

electronegativity of Cobalt  1.88

electronegativity of Nickel  1.91

As the electronegativity of aluminium is lower as compared to other, so it will have high tendency to easily lose electron and that is why Aluminium is more reactive than the other mentioned

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8 0
3 years ago
How many moles of lithium nitrate<br> (LINO3) are in 256 mL of a 0.855 M<br> solution?
sweet [91]

Answer:

There are 0.219 mol of LINO3

7 0
3 years ago
Calculate the theoretical atom economy for each reaction.
Arisa [49]
100% find the gfm of both sides then divide 
4 0
3 years ago
In an electrically heated boiler, water is boiled at 140°C by a 90 cm long, 8 mm diameter horizontal heating element immersed in
RideAnS [48]

Explanation:

The given data is as follows.

Volume of water = 0.25 m^{3}

Density of water = 1000 kg/m^{3}

Therefore,  mass of water = Density × Volume

                       = 1000 kg/m^{3} \times 0.25 m^{3}

                       = 250 kg  

Initial Temperature of water (T_{1}) = 20^{o}C

Final temperature of water = 140^{o}C

Heat of vaporization of water (dH_{v}) at 140^{o}C  is 2133 kJ/kg

Specific heat capacity of water = 4.184 kJ/kg/K

As 25% of water got evaporated at its boiling point (140^{o}C) in 60 min.

Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg

Heat required to evaporate = Amount of water evapotaed × Heat of vaporization

                           = 62.5 (kg) × 2133 (kJ/kg)

                           = 133.3 \times 10^{3} kJ

All this heat was supplied in 60 min = 60(min)  × 60(sec/min) = 3600 sec

Therefore, heat supplied per unit time = Heat required/time = \frac{133.3 \times 10^{3}kJ}{3600 s} = 37 kJ/s or kW

The power rating of electric heating element is 37 kW.

Hence, heat required to raise the temperature from 20^{o}C to 140^{o}C of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)

                      = 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)

                     = 125520 kJ  

Time required = Heat required / Power rating

                       = \frac{125520}{37}

                       = 3392 sec

Time required to raise the temperature from 20^{o}C to 140^{o}C of 0.25 m^{3} water is calculated as follows.

                    \frac{3392 sec}{60 sec/min}

                     = 56 min

Thus, we can conclude that the time required to raise the temperature is 56 min.

4 0
3 years ago
Write the complete balanced equation for the reaction between CaCO3 and KCI
EleoNora [17]

CaCO3 + 2KCL ⇒ CaCl2 + K2CO3

It is balanced as so based on the charges given on the periodic table and polyatomic ions.

Calcium has the charge of 2 but CO3 also shares the same charge, thus cancelling that out.

Potassium has a charge of 1 while Chlorine also shares a charge of 1, also cancelling it out.

Thus, if it performs a double replacement reaction, they would take these charges to the new elements that do not cancel out their charges.

Therefore, we need the coefficient of 2 in front of Potassium Chloride in order to balance the equation as on the products side of the equation, Potassium and Chlorine both have a subscript of 2.

Hope this helps!

5 0
3 years ago
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