For the answer to the question above asking w<span>hen an atom of n-14 is bombarded by an alpha particle, the single product is?
</span> <span>You're starting with 14/7 N, correct?
An alpha particle is two protons, two neutrons, which is 4/2, correct?
</span><span>So I</span> think the answer to your question is the third one which is <span>c. 18/9 f </span>
The structure is in attachment.
Hexane is alkane (acyclic saturated hydrocarbon, carbon-carbon bonds<span> are </span>single) <span>of six </span>carbon atoms. Methoxy<span> group is the functional group consisting of a methyl group bound to oxygen. Iodo is substituent consists of ionide (element in 17 periodic group).</span>
You can establish a system of two equation with two variables.
Varibles are:
V1 = volume of the 50% sugar solution
V2 = volumen of the 80% sugar solution
Equations:
Balance of sugar:
Sugar from 50% solution: 0.5*V1
Sugar from 80% solution: 0.8*V2
Sugar in the final solution (mix): 0.6 * 105 = 63
1) 0.5V1 + 0.8V2 = 63
Final volume = volume of 50% solution + volume of 80% solution
2) V1 + V2 = 105
From (2) V1 = 105 - V2
Substitue in (1)
0.5 (105 - V2) + 0.8 V2 = 63
52.5 - 0.5V2 + 0.8V2 = 63
0.3 V2 = 63 - 52.5
0.3 V2 = 10.5
V2 = 10.5/0.3
V2 = 35mL
V1 = 105 - 35 = 70 mL
Answer: 70 mL of the 50% solution and 35 mL of the 80% solution.
true, in a stronger gravitational field the weight will be larger.
