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Rudik [331]
3 years ago
6

What is one molar volume of the gas ammonia (nh3) at stp?

Chemistry
2 answers:
Sedbober [7]3 years ago
6 0
<span>The molar volume of ammonia at standard temperature and pressure (STP) is 22.4L. This is the standard molar volume of any gas at these conditions.</span>
OverLord2011 [107]3 years ago
5 0

Answer:

22.4 L is incorrect,  the answer is a little  less than 22.4

Explanation:

Why, because ammonia is not and ideal gas, it is a real gas.

Any ideal gas, does have a molar volume of 22.4 L at STP

The ammonia, molecule is very polar, that is why we can do an ammonia fountain.  The ammonia molecules are attracted to each other. and therefore a mole of ammonia gas (NH3) will occupy less than the 22.4 L than an ideal gas such as an inert gas would occupy.

I am a retired H. S. teacher and taught chemistry and then advanced placement chem.   As a review, and skipping the details. here is an investigation we did at the beginning of the AP chem class.  I have never seen it in a textbook.

After the first day of class a volunteer group of students standardized HCL to 0.100N, , or I did it myself.

Did ammonia fountain.  Put a small amount of phenolphthalein in the water before doing the fountain , for the fun of it- getting the pink ammonia solution

Collected 100.0 ml of the ammonia solution, titrated it with the 0.100N HCL  

Used pH meters which were more accurate, because the pH transition of the phenolphthalein  is about 8 or 9 or above.  

Knowing the amount (number of HCl molecules used to titrate and the balanced equation shows we had an equal number of NH3 in the 100.0 ml that were titrated.  

Took a ratio to determine what volume a mole of NH3 would occupy and then adjusted that value to STP.  

Used the collective class results,  and found we had very good precision. but knowing the molar volume of an idea gas, we knew the mean value was somewhat  low.  The question for the next day was why?  Some students were able to determine (after prodding and drawing a picture of the molecule showing its polarity) ,that NH3 is not an ideal gas.  

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When 0.42 g of a compound containing C, H, and O is burned completely, the products are 1.03 g CO2 and 0.14 g H2O. The molecular
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<u>Answer:</u> The empirical and molecular formula for the given organic compound is C_2H_2O_4 and C_6H_4O_2

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=1.03g

Mass of H_2O=0.14g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 1.03 g of carbon dioxide, \frac{12}{44}\times 1.03=0.28g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.14 g of water, \frac{2}{18}\times 0.14=0.016g of hydrogen will be contained.

  • Mass of oxygen in the compound = (0.42) - (0.28 + 0.016) = 0.124 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.28g}{12g/mole}=0.023moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.016g}{1g/mole}=0.016moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.124g}{16g/mole}=0.00775moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00775 moles.

For Carbon = \frac{0.023}{0.00775}=2.96\approx 3

For Hydrogen  = \frac{0.016}{0.00775}=2.06\approx 2

For Oxygen  = \frac{0.00775}{0.00775}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 2 : 1

Hence, the empirical formula for the given compound is C_3H_{2}O_1=C_3H_2O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 108.10 g/mol

Mass of empirical formula = 54 g/mol

Putting values in above equation, we get:

n=\frac{108.10g/mol}{54g/mol}=2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(3\times 2)}H_{(2\times 2)}O_{(1\times 2)}=C_6H_4O_2

Thus, the empirical and molecular formula for the given organic compound is C_3H_2O and C_6H_4O_2

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As the population in a small town grows, a new water treatment plant is built. The plant is built on a local river where it can
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The element with the lowest melting point is Ga.
Hence, Option (C) is correct answer.

<h3>What is Melting point ?</h3>

Melting point is usually defined as the temperature at which solid changes to liquid.

<h3>What is the order of melting point of  B, Al, Ga, Tl ?</h3>

The melting point order of B, Al, Ga, Tl is B > Al> Tl > Ga due to structural changes, melting point increases from Ga to Tl. Hence Ga has the lowest melting point among all these.

Thus from the above conclusion we can say that The element with the lowest melting point is Ga.
Hence, Option (C) is correct answer.

Learn more about the Melting Point here: brainly.com/question/40140

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