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Ksivusya [100]
3 years ago
13

What information does an equilibrium constant give about a reaction?

Chemistry
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

B. It tells whether products or reactants are favored at equilibrium.

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5.(a) Give the names and symbols of respective elements. (5)
Leya [2.2K]

Answer:

Elements:

Platinum - Pt

Silicon - Si

Lead - Pb

Hydrogen- H

Silver - Ag

Symbols:

Pr - Praseodymium

K - Potassium

Br - Bromine

Mg - Magnesium

Hg - Mercury

6 0
2 years ago
Potassium and iodine have formed a bond. Prior to this the potassium gave up an electron. It became a _____.
Sliva [168]
Neutral ion because     f das fds f d fd f d f  f sdf  f sd  fds
6 0
3 years ago
Read 2 more answers
HELP AGAIN PLSS:
murzikaleks [220]
This is true


Because when water evaporates molecules break and separate into different atoms
4 0
2 years ago
Which of the following BEST describes a change in Earth’s atmosphere made by early photosynthetic life?
swat32

A

It is referred to as the Great Oxygenation Event. During this time, photosynthetic organisms evolved and begun utilizing sunlight for energy. They captured this energy into chemical energy. These organisms took up carbon dioxide and evolved oxygen  into the atmosphere.

Explanation:

Oxygen levels in the atmosphere rose drastically as those of carbon dioxide and methane dropped. This increase of oxygen in the atmosphere also allowed the formation of an ozone layer that protects genetic material from UV light. This largely enabled organisms to conquer land.

Learn More:

For more on the Great Oxygenation Event check out;

brainly.com/question/11255683

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5 0
3 years ago
PH =5 and now to prepare a buffer solution what will be the proportion of ethanoic acid and sodium ethanoate
Alik [6]

Answer:

CH3COONa : CH3COOH =  1.74 :  1  (required to prepare a buffer at PH = 5)

Explanation:

Given that :

PH = 5

Calculate proportions of ethanoic acid and Sodium ethanoate to prepare Buffer solution

solution :  

PH = Pka + Log ( CH3COONa / CH3COOH )

5.0 = 4.76 +  Log ( CH3COONa / CH3COOH )

∴  Log ( CH3COONa / CH3COOH ) = 0.24

( CH3COONa / CH3COOH )  = 1.74

Therefore : CH3COONa : CH3COOH

                         1.74          :      1

4 0
3 years ago
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