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garik1379 [7]
3 years ago
13

[Please help fast! Offering 100 points if it works!}

Physics
2 answers:
Alex17521 [72]3 years ago
8 0

(8.3 min)/(1 AU) = (T)/(1.52 AU)

(8.3 min)x(1.52 AU) = (T x 1 AU)

T = (8.3 min x 1.52 AU) / (1 AU)

T = 12.62 minutes

solmaris [256]3 years ago
3 0

Answer:

d=1.49×1011m

Explanation:

Velocity is defined as the rate of travel, and can be found using the distance formula.

velocity=distancetime

Rearranging this formula we can solve for distance given velocity and time of travel.

d=vt

We are given velocity and time, and so can solve for distance, but if we plug in the values given;

d=(3.00×108m/s)(8.3minutes)

We can see that the units do not match up. Since seconds are the SI unit for time, we will need to convert 8.3 minutes to seconds.

t=(8.3minutes)(60seconds/minute)=(498s)

Now our units work out and we can solve for distance.

= 15.85

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A student stretches an elastic band by 0.8 m in 0.5 seconds. The spring constant of the elastic band is 40 N/m. What was the pow
miv72 [106K]

Answer:

The power exerted by the student is 51.2 W

Explanation:

Given;

extension of the elastic band, x = 0.8 m

time taken to stretch this distance, t = 0.5 seconds

the spring constant, k = 40 N/m

Apply Hook's law;

F = kx

where;

F is the force applied to the elastic band

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The power exerted by the student is calculated as;

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P = 32 x (0.8 /0.5)

P = 32 x 1.6

P = 51.2 W

Therefore, the power exerted by the student is 51.2 W

3 0
3 years ago
Answer this and you get 100 points<br> You better answer it quick though
solong [7]

Answer what? Apologies, but I don't see anything. (。>︿<)

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3 years ago
The splitting of light into its component parts is referred to as which of the following?
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A student practicing for a track meet ran 250 m in 30 seconds. What was her average speed?
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3 years ago
Read 2 more answers
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