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wlad13 [49]
3 years ago
13

What weather would create the weakest surfing waves?

Physics
1 answer:
ella [17]3 years ago
5 0
Its B hope I could help
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An object is released from height of 17m. <br> The object will hit the ground approximately in
zzz [600]

\text{Given that,}\\\\\text{Height, h = 17 m}\\\\\\\text{We know that,}\\\\h = v_0t + \dfrac 12  gt^2\\\\\implies h = \dfrac 12 gt^2\\\\\implies t^2 = \dfrac{2h}g\\\\\implies t =\sqrt{\dfrac{2h}g} = \sqrt{\dfrac{2(17)}{9.81}} = 1.87 ~ \text{sec}

5 0
2 years ago
Is it possible to apply the same amount of force and do different amounts of work?
Tamiku [17]
Yes, with simple machines
5 0
3 years ago
Match the organs to the functions they perform during digestion.<br> passes food to esophagus
mixas84 [53]

Answer:

the mouth I think

Because: the oesophagus is the throat and the mouth is how the food gets to the oesophagus. might be wrong because I'm not sure about the organ part but I'm pretty sure that's all it could be

8 0
3 years ago
How much energy (in Joules) is released when 12.0 g of water cools from 20.0 °C to 11.0 °C? This is a grade 10 question from the
KATRIN_1 [288]

Answer: - 452.088joule

Explanation:

Given the following :

Mass of water = 12g

Change in temperature(Dt) = (11 - 20)°C = - 9°C

Specific heats capacity of water(c) = 4.186j/g°C

Q = mcDt

Where Q = quantity of heat

Q = 12g × 4.186j/g°C × - 9°C

Q = - 452.088joule

7 0
3 years ago
What is a gravitational field and how its strength be measured
Yakvenalex [24]
A gravitational field is the field generated by a massive body, that extends into the entire space. Every object with mass m experiences a force F when immersed in a gravitational field. The intensity of the force is equal to
F= \frac{GM}{r^2}  m
where G=6.67 \cdot 10^{-11} m^3 Kg^{-1} s^{-2} is the gravitational  constant, M is the mass of the source of the field (e.g. the mass of a planet), and r is the distance between the object and the source of the field. The force is always attractive. 

A possible way to measure the intensity of a gravitational field is by measuring the acceleration a of the object immersed in this field. In fact, for Newton's second law we have:
F=ma
but since 
F= \frac{GM}{r^2} m
we can write
a =  \frac{GM}{r^2}
Therefore, by measuring the acceleration of the object, we also measure the intensity of the field.

5 0
3 years ago
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