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Evgesh-ka [11]
3 years ago
7

A substance has a mass of 360 g and a volume of 7.5 cm3. What is its density?. a.. 2700 g/cm3. c.. 480 g/cm3. b.. 270 g/cm3. d..

48 g/cm3.
Chemistry
2 answers:
bogdanovich [222]3 years ago
5 0
D = m / V

D = 360 / 7.5

D = 48 g/cm³

Answer D

hope this helps!
Darya [45]3 years ago
3 0
Mass of the substance in question = 360 g
Volume of the substance in question = 7.5 cm^3
We already know that
Density of the substance = Mass of the substance / Volume of the substance
                                         = 360/7.5 g/cm^3
                                         = 48 g/cm^3
So the correct option among all the options that are given in the question is the fourth option or option "d". I hope the answer comes to your help.
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Hybrid Orbitals: are used to describe the orbitals in covalently bonded atoms sp,sp2,sp3

You can find the hybridization by adding the number of bonded atoms and the number of lone pairs.

For example in BF3. The central atom (B) is bonded to three atoms. So the hybridization is sp2

In NH3, the central atom (N) is bonded to three atoms and has one lone pair. The hybridization is sp3
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3 years ago
Indicate the electron pair geometry and the molecular geometry for each of the six compounds. Compound Electron pair geometry Mo
marusya05 [52]

Answer:

CO2

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Molecular geometry- Linear

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Electron pair geometry - Trigonal planar

Molecular geometry- trigonal planar

SO2

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Molecular geometry - bent

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Electron geometry- tetrahedral

Molecular geometry - tetrahedral

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Electron pair geometry - tetrahedral

Molecular geometry- trigonal pyramidal

OF2

Electron pair geometry- tetrahedral

Molecular geometry- bent

Explanation:

Considering the molecule CO2, there are two regions of electron density in the molecule positioned at an angle of 180 degrees from each other hence the molecule is linear.

For BF3, the three bond pairs are arranged at the corners of a triangle to give a trigonal planar geometry at a bond angle of 120 degrees.

SO2 has two bonding groups and one lone pair giving three regions of electron density and a trigonal planar electron pair geometry. Due to the distortion to geometry caused by the presence of a lone pair, the molecule is bent.

For SiCl4, the four bonding groups are arranged at the corners of a regular tetrahedron hence it is tetrahedral both in electron pair geometry and in molecular geometry.

PF3 molecule has four regions of electron density corresponding to tetrahedral electron pair geometry. The presence of the lone pair leads to a trigonal pyramidal molecular geometry.

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5 0
3 years ago
Fe2O3(s) + 3CO(g) ---> 2Fe(l) + 3CO2(g) Steve inserts 450. g of iron(III) oxide and 260. g of carbon monoxide into the blast
baherus [9]

Answer: Theoretical yield is 313.6 g and the percent yield is, 91.8%

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe_2O_3=\frac{450}{160}=2.8moles

\text{Moles of} CO=\frac{260}{28}=9.3moles

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(l)+3CO_2(g)

According to stoichiometry :

1 mole of Fe_2O_3 require 3 moles of CO

Thus 2.8 moles of Fe_2O_3 will require=\frac{3}{1}\times 2.8=8.4moles  of CO

Thus Fe_2O_3 is the limiting reagent as it limits the formation of product and CO is the excess reagent.

As 1 mole of Fe_2O_3 give = 2 moles of Fe

Thus 2.8 moles of Fe_2O_3 give =\frac{2}{1}\times 2.8=5.6moles of Fe

Mass of Fe=moles\times {\text {Molar mass}}=2.6moles\times 56g/mol=313.6g

Theoretical yield of liquid iron = 313.6 g

Experimental yield = 288 g

Now we have to calculate the percent yield

\%\text{ yield}=\frac{\text{Actual yield }}{\text{Theoretical yield}}\times 100=\frac{288g}{313.6g}\times 100=91.8\%

Therefore, the percent yield is, 91.8%

6 0
3 years ago
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forsale [732]

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