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cluponka [151]
3 years ago
9

If the specific heat capacity of water is 4.19 J/(g⋅K), how much energy would be required to raise the temperature of 100.0 g of

water by 2.00 °C?
Chemistry
1 answer:
Novosadov [1.4K]3 years ago
3 0
<h3>Answer:</h3>

838 Joules

<h3>Explanation:</h3>
  • To calculate amount of heat required we multiply mass of water by the specific heat capacity and then by change in temperature.
  • That is; Q =m×c×ΔT

We are given;

Specific heat capacity of water, c = 4.19 J/g.K

Mass of water, m = 100.0 g

Change in temperature, ΔT = 2.00°C or 2 K

Therefore;

Q = mcΔT

  = 100 g ×  4.19 J/g.K × 2K

  = 838 Joules

Thus, the energy required is 838 Joules

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