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cluponka [151]
3 years ago
9

If the specific heat capacity of water is 4.19 J/(g⋅K), how much energy would be required to raise the temperature of 100.0 g of

water by 2.00 °C?
Chemistry
1 answer:
Novosadov [1.4K]3 years ago
3 0
<h3>Answer:</h3>

838 Joules

<h3>Explanation:</h3>
  • To calculate amount of heat required we multiply mass of water by the specific heat capacity and then by change in temperature.
  • That is; Q =m×c×ΔT

We are given;

Specific heat capacity of water, c = 4.19 J/g.K

Mass of water, m = 100.0 g

Change in temperature, ΔT = 2.00°C or 2 K

Therefore;

Q = mcΔT

  = 100 g ×  4.19 J/g.K × 2K

  = 838 Joules

Thus, the energy required is 838 Joules

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Answer:

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Explanation:

According to Coulomb's law, the force between two species is inversely proportional to the distance between them. That said, the bigger the atoms are, the greater the bond length should be to form a molecule.

As a result, for a greater bond length, the attraction force is lower than for a shorter bond length. This implies that large atoms would form weak bonds and small atoms would form strong bonds.

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6 0
3 years ago
How many joules of heat are required to heat 110 g of aluminum from 52.0 oC to 91.5 oC?
docker41 [41]

Answer:

We need 3910.5 joules of energy

Explanation:

Step 1: Data given

Mass of aluminium = 110 grams

Initial temperature = 52.0 °C

Final temperature = 91.5 °C

Specific heat of aluminium = 0.900 J/g°C

Step 2: Calculate energy required

Q = m*c*ΔT

⇒with Q = the energy required = TO BE DETERMINED

⇒with m = the mass of aluminium = 110 grams

⇒with c = the specific heat of aluminium = 0.900 J/g°C

⇒with ΔT = the change in temperature = T2 - T1 = 91.5 °C - 52.0 °C = 39.5 °C

Q = 110 grams * 0.900 J/g°C * 39.5

Q = 3910.5 J

We need 3910.5 joules of energy

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