Ask question

Ask question

All categories

3 years ago

7

How do you find a rate of deceleration

2 answers:

maxonik [38]3 years ago

7 0

To find the deceleration of the object. We need to know what is the speed the object is slowing down to, in this case it would be final velocity of 0.

Vi = 75
Vf = vi + at
0 = 300a + 75
-75 m/s = 300a
-75/300 = a
-0.25 m/s^2 = a.

The train slows down at this rate a = -0.25 m/s^2.

5 min = 5 • 60 = 300 seconds

Irina18 [472]3 years ago

4 0

To find the rate of deceleration, subtract the initial velocity from the final velocity.

You might be interested in

Two identical charges, 2 m apart, exert forces of magnitude 4 N on each other. The value of each charge is: 1. 9 × 105 C 2. 4.2

lesya692 [45]

Answer:

The value of each charge is 4.22 x 10⁻⁵ C

Explanation:

Given;

distance between the two identical charges, d = 2 m

the force of repulsion between these two charges, F = 4N

Apply Coulomb's law;

$F = \frac{kq_1q_2}{r^2} \\\\but \ q_1 =q_2,then \ let \ q_1 =q_2 = q\\\\F = \frac{kq^2}{r^2}\\\\q^2 = \frac{Fr^2}{k}\\\\q^2 = \frac{4*2^2}{9*10^9} \\\\q ^2 = 1.7778*10^{-9}\\\\q = \sqrt{1.7778*10^{-9}}\\\\q =4.22 *10^{-5} C\\\\q= q_1=q_2= 4.22 *10^{-5} C$

Therefore, the value of each charge is 4.22 x 10⁻⁵ C

7 0

3 years ago

Which of the following examples does not make use of total internal reflection?

liubo4ka [24]

Answer:

laser pointer does not make use of total internal reflection

7 0

3 years ago

Three joules of work is needed to shift 10 C of charge from one place to another. The potential difference between the places is

dimaraw [331]

Answer:

The potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

Explanation:

Given

Work done W = 3J

Amount of Charge q = 10C

To determine

We need to determine the potential difference V between the places.

The potential difference between the two points can be determined using the formula

Potential Difference (V) = Work Done (W) / Amount of Charge (q)

or

$\:V\:=\:\frac{W}{q}$

substituting W = 3 and q = 10 in the formula

$V=\frac{3}{10}$

$V=0.3$ V

Therefore, the potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

4 0

3 years ago

How much force does it take to bring a 1,375 N car from rest to a velocity of 26 m/s in 6 seconds?

V125BC [204]

Explanation:

<u>Mass of car</u> = 137.5 kg

<u>Acceleration</u> = v - u / t = 26 - 0 / 6 = 4.33 m/sec^2

Force = m * a = 137.5 * 4.33 = 595.3 N

6 0

3 years ago

a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car

uysha [10]

Answer:

= 201.53 meters

Explanation:

A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?

Use the formula d = $\frac{at^{2} }{2} ,$

where d is the distance, t is the time and "a" is the acceleration.
$d=\frac{9*54*6*5^{2} }{2} = 201.53 m$

3 0

2 years ago