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3 years ago

Describe another real-world example of a perfectly inelastic collision

Physics

2 answers:

Sidana [21]3 years ago

8 0

1. Newtons Cradle
2. When you play pool and one ball transfers all its momentum, making the first ball come to a halt.

Ivahew [28]3 years ago

5 0

<span>An example of a perfectly elastic collision is that it doesn't exist. But for the sake of saying it exist you would assume that a collision takes place where energy is completely conserved and is not lost as (non-usable energy) heat. Maybe you say that a gas molecule collides with a completely (perfectly) smooth surface and the gas molecules collides perpendicular to the surface (does not collide at an angle). The gas molecule then bounces off the wall with the same speed as when it colliding against the wall. This would assume a perfectly elastic collision as KE=1/2mv^2. When your gas molecule collides its mass doesn't change but when you say that the gas molecule had the same velocity when it bounces off the wall you ahve assumed that kinetic energy is maintained (which assumes perfectly elastic).</span>

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A) Give 3 examples of forces that are pulls and 3 examples that are pushes. b) For each example you give, state an approximate v

Stels [109]

Answer:

Explanation:

Force is defined as the push or pull which changes or tries to change the position, state of motion and the shape of the object.

(A) The examples of push are:

To push a chair on the floor, to push the car when it is stopped due to some problem, to push book on the table.

The examples of pull are :

To pull a chair towards you, to pull a string in a game of top, to pull the string in a gym.

(B) To push a chair or a book, the force required is small as compared to the to push a car.

To pull a chair or the string of top is less than the force to pull the string in gym.

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2 years ago

Two solenoids are equal in length and radius, and the cores of both are identical cylinders of iron. However, solenoid A has fou

Ira Lisetskai [31]

Answer:

$\dfrac{L_A}{L_B}=16$

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi \times 10^{-7}\ H/m$

n = Number of turns

A = Area

I = Current

Self inductance is given by

$L=\mu_0n^2IA$

Here, A has more turns so the self-inductance of A will be higher

For A

$L_A=\mu_0n_A^2IA=\mu_0(4n_B)^2IA$ $[\because n_A=4n_B]$

For B

$L_B=\mu_0n_B^2IA$

Dividing the above two equations we have

$\dfrac{L_A}{L_B}=\dfrac{\mu_0(4n_B)^2IA}{\mu_0n_B^2IA}\\\Rightarrow \dfrac{L_A}{L_B}=16$

$\therefore \dfrac{L_A}{L_B}=16$

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2 years ago

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Tarnish is produced by a redox reaction that occurs when a metal reacts with

Dvinal [7]

Answer:

Copper atoms lose electrons to sulfur atoms

Explanation:

a p e x (:

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2 years ago

Calculate the heat flux (in W/m^2) through a sheet of a metal 14 mm thick if the temperatures at the two faces are 350 and 140°C

ExtremeBDS [4]

Answer:

Explanation:

The rate of conductive heat transfer in watts is:

q = (k/s) A ΔT

where k is the heat conductivity, s is the thickness, A is the area, and ΔT is the temperature difference.

Given k = 52.4 W/m/K, s = 0.014 m, and ΔT = 350-140 = 210 K, we can find q/A:

q/A = (52.4 / 0.014) (210)

q/A = 786,000 W/m²

Given that A = 0.42 m², we can find q:

q = (0.42 m²) (786,000 W/m²)

q = 330,120 W

A watt is a Joule per second. Convert to Joules per hour:

q = 330,120 J/s * 3600 s/hr

q = 1.19×10⁹ J/hr

If we change k to 1.8 W/m/K:

q = (k/s) A ΔT

q = (1.8 / 0.014) (0.42) (210)

q = 11,340 J/s

q = 4.08×10⁷ J/hr

If k is 52.4 W/m/K and s is 0.024 m:

q = (k/s) A ΔT

q = (52.4 / 0.024) (0.42) (210)

q = 192,570 J/s

q = 6.93×10⁸ J/hr

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2 years ago

How is climate different from weather?

olga55 [171]

Climate is the average weather type throughout the year while weather is something that can happen just once a day, not the average though.

5 0

3 years ago

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