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Minchanka [31]
3 years ago
10

You sent 85 text messages in one month. the total cost is $5.1. how much does each text message cost?

Mathematics
1 answer:
tresset_1 [31]3 years ago
7 0
5.10÷85=$0.06<---

check your answer
85×0.06=$5.10
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PQRS is a trapezoid with a right angle. What are the coordinates of S
Brrunno [24]

Answer: (a, 0)

<u>Step-by-step explanation:</u>

Notice that S is on the x-axis, therefore the y-coordinate is "0".

Notice that S has the same x-value of R. The x-value of R is "a".

8 0
3 years ago
Richie spent $120 on 12 rose bushes and 2 gardenias, while Jim spent it $150 on 10 rose bushes and 10 gardenias. What is the cos
Basile [38]
With the given information, we can create several equations:

120 = 12x + 2y
150 = 10x + 10y

With x being the number of rose bushes, and y being the number of gardenias.

To find the values of the variables, we can use two methods: Substitution or Elimination

For this case, let us use elimination. To begin, let's be clear that we are going to be adding these equations together. Therefore, in order to get the value of one variable, we must cancel one of them out - it could be x or y, it doesn't matter which one you decide to cancel out. Let's cancel the x out:

We first need to multiply the equations by numbers that would cause the x's to cancel out - and this can be done as follows:

-10(120 = 12x + 2y)
 12(150 = 10x + 10y) => Notice how one of these is negative

Multiply out:

    -1200 = -120x - 20y
 +  1800 =  120x + 120y          => Add these two equations together
---------------------------------
600 = 100y

Now we can solve for y:

y = 6

With this value of y known, we can then pick an equation from the beginning of the question, and plug y in to solve for x:

120 = 12x + 2y    =>    120 = 12x + 2(6)

Now we can solve for x:

120 = 12x + 12    =>     108 = 12x

x = 9

So now we know that x = 9, and y = 6.

With rose bushes being x, we now know that the cost of 1 rose bush is $9.
With gardenias being y, we now know that the cost of 1 gardenia is $6.  
4 0
3 years ago
I don't understand how to solve this, please help!
murzikaleks [220]

Answer:

x+1 , x<-1

x²-bx-4  , -1≤x≤4

1/2 x +a

substitute x=-1 , continuous everywhere

x+1=x²-bx-4 when x=-1

-1+1=-1²-b-4

<h2>1+b-4=0 ⇒ +b-3 ⇒ b=3</h2>

then for :

x²-bx-4=1/2 x +a for x=4

4²-4b-4=1/2x+a

16-4(3)-4=4/2+a

16-12-4-2=a

<h2>a=-2</h2>

the equations will be :

x+1

x²-3x-4

1/2x-2

I hope this help

7 0
3 years ago
A multiple of 9 with the tens digit that is more than the units digit​
Colt1911 [192]

Answer:

81, tens place is 8 ,unit's pkace is 1, so 8>1, that satisfies.

7 0
3 years ago
Find any 3 (x,y) pairs that are solutions for the equation 2x-5y=10 . Show your work
Alla [95]

Answer:

(0,-2), (5,0) and (10,2).

Step-by-step explanation:

Given equation is 2x-5y=10.

Now we need to find 3 pairs of solutions in (x,y) form for the given equation.

As 2x-5y=10 is a linear equation so we are free to pick any number for x like x=0, 5, 10

Plug x=0 into 2x-5y=10, we get:

2(0)-5y=10

0-5y=10

-5y=10

y=\frac{10}{-5}

y=-2

Hence first solution is (0,-2)

We can repeat same process with x=5 and 10 to get the other solutions.

Hence final answer is (0,-2), (5,0) and (10,2).

5 0
3 years ago
Read 2 more answers
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