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slava [35]
3 years ago
5

What is the most likely decay for the fe-53 nucleus?

Chemistry
1 answer:
svetoff [14.1K]3 years ago
7 0
The element number of Fe is 26, which means that the number of neutrons of the following isotopes is: 

<span>53-Fe: 27 </span>
<span>54-Fe: 28 </span>
<span>56-Fe: 30 </span>
<span>57-Fe: 31 </span>
<span>58-Fe: 32 </span>
<span>59-Fe: 33 </span>

<span>Because 53-Fe has too few neutrons when compared to the other isotopes we can rule out any decay that involves losing a neutron: (alpha decay, beta decay) So, this isotope will prefer to decay by electron capture or positron emission (assuming the system has about 1 MeV to spare), but in each case the product will be the same: 53-Mn (long-lived radioisotope). </span>


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Sloan [31]

Answer:

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Explanation:

3 0
3 years ago
How many atoms are present in a sample of Potassium (K) weighing 33.49g?
madam [21]

Answer:

5.158 × 10²³ atoms K

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

33.49 g K

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of K - 39.10 g/mol

<u>Step 3: Convert</u>

<u />33.49 \ g \ K(\frac{1 \ mol \ K}{39.10 \ g \ K} )(\frac{6.022 \cdot 10^{23} \ atoms \ K}{1 \ mol \ K} ) = 5.15797 × 10²³ atoms K

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig figs and round.</em>

5.15797 × 10²³ atoms K ≈ 5.158 × 10²³ atoms K

3 0
3 years ago
What is the major cause of erosion and weathering that affects coastline features?
Arisa [49]

Answer:

Image result for What is the major cause of erosion and weathering that affects coastline features?

Coastal erosion, which is the wearing away of coastal land or beaches, is mainly caused by the impact of waves along the shoreline. This is accentuated during storms when waves are large and crash on shore with a lot of energy. ... As the sand and rocks crash into the coast, they grind away land and rock.

Explanation:

7 0
3 years ago
A 25.00 mL sample of of a sulfurous acid solution is completely neutralized using 17.12 mL of 0.13 M sodium hydroxide. What is t
Kryger [21]

Answer:

0.0445 M is the initial concentration of sulfurous acid.

Explanation:

H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_3

are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=25.00mL\\n_2=1\\M_2=0.13 M\\V_2=17.12 mL

Putting values in above equation, we get:

2\times M_1\times 25.00 mL=1\times 0.13 M\times 17.12 mL

x=\frac{1\times 0.13 M\times 17.12 mL}{2\times 25.00}=0.0445 M

0.0445 M is the initial concentration of sulfurous acid.

8 0
3 years ago
2. Which test for iron(II) ions is conclusive ​
krok68 [10]

Answer:

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Explanation:

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3 years ago
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