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TiliK225 [7]
3 years ago
10

Briefly explain how magnetic behavior is related to the arrangement of valence electrons in the outer orbitals

Chemistry
1 answer:
olga nikolaevna [1]3 years ago
3 0

Answer:

Elements with unpaired valence electrons in the outer orbital are paramagnetic. Elements that are predicted to exhibit paramagnetic behavior may exhibit ferromagnetic behavior. Elements that contain only paired valence electrons are diamagnetic.

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Calculate the molar mass for each of the following:
Mila [183]

Answer: a . 152g/mol  b. 102g/mol c. 183g/mol

Explanation:

By stating the atomic masses of each element in the questions, we have;

Fe= 56, S= 32, O= 16, Al = 27, C = 12, H =1 , N = 14, therefore

(a). FeSO4 =  56 + 32 + (16 x 4) =  152g/mol

(b). Al2O3 =  (27 x 2) + (16 x 3) = 102g/mol

(c). C7H5NO3S ( Saccharin, an artificial Sweetner) =

   (12 x 7) + (1 x 5) + 14 + (16 x 3) + 32 =  183g/mol

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3 years ago
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Answer:

Hypernantremia due to excess water loss

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5 0
1 year ago
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What is an isotope?
Marysya12 [62]

Answer:

C: Atoms of the same element that have similar chemical properties but have different  numbers of neutrons

<u><em>Could I please have BRAINLIEST.</em></u>

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3 years ago
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What volume did a helium-filled balloon have at 22.5 c and 1.95 atm if it’s new volume was 56.4 mL at 3.69 atm and 11.9c
Veseljchak [2.6K]

This is an exercise in the general or combined gas law.

To start solving this exercise, we obtain the following data:

<h3>Data:</h3>
  • T₁ = 22.5 °C + 273 = 295.5 K
  • P₁ = 1.95 atm
  • V₁ = ¿?
  • P₂ = 3.69 atm
  • T₂ = 11.9 °C + 273 =  284.9 k
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We use the following formula:

P₁V₁T₂ = P₂V₂T₁ ⇒ General formula

Where

  • P₁ = Initial pressure
  • V₁ = Initial volume
  • T₂ = Initial temperature
  • P₂ = Final pressure
  • V₂ = final volume
  • T₁ = Initial temperature

We clear the formula for the initial volume:

\boldsymbol{\sf{V_{1}=\dfrac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}  } }

We substitute our data into the formula to solve:

\boldsymbol{\sf{V_{1}=\dfrac{(3.69 \not{atm})(56.4 \ ml)(295.5 \not{k})}{(1.95 \not{atm})(284.9\not{k})}  }}

\boldsymbol{\sf{V_{1}=\dfrac{61498.278}{555.555} \ lm }}

\boxed{\boldsymbol{\sf{V_{1}=110.697 \ lm }}}

The helium-filled balloon has a volume of <u>110.697 ml.</u>

6 0
1 year ago
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How does understanding chemistry help us in the real world?
Archy [21]

Answer:

D

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It indeed does keep us from doing dangerous things, considering the fact that chemistry is done everywhere.

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3 years ago
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