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4 years ago

Briefly explain how magnetic behavior is related to the arrangement of valence electrons in the outer orbitals

Chemistry

1 answer:

olga nikolaevna [1]4 years ago

3 0

Answer:

Elements with unpaired valence electrons in the outer orbital are paramagnetic. Elements that are predicted to exhibit paramagnetic behavior may exhibit ferromagnetic behavior. Elements that contain only paired valence electrons are diamagnetic.

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PLEASE HELP! DUE IN 5 MINS SUPER EASY CHEMISTRY!!

lbvjy [14]

Answer:

Explanation:

Since they all are 2 mols worth, all you have to do is count the number of atoms in each molecule

H2SO4 contains 2 hydrogen 1 sulfur 4 oxygen = 7 atoms

H2S contains 2 hydrogen and 1 sulfur = 3 atoms

H3PO4 contains 3 hydrogens 1 phosphorus 4 oxygens = 8 atoms

HNO3 contains 1 hydrogen 1 nitrogen and 3 oxygens = 5 atoms

You have the right answer.

5 0

3 years ago

What is the purpose of an experimental group?

zepelin [54]

Answer:

the purpose of an experimental group are:

to enable the experimental study of one variable at a time
to check a different result

5 0

3 years ago

Read 2 more answers

How many different values of ml are possible in the 2p sublevel?

Kisachek [45]

There are four quantum numbers for an orbital, namely, principal quantum number n, azimuthal quantum number l, magnetic quantum number $m_{l}$ and spin quantum number s. No two orbitals can have same value for all the four quantum numbers.

Principal quantum number tells about the position of orbital that is shell number, azimuthal quantum number describes the shape of orbital, for s, p, d, f,... orbitals, the value is 0, 1, 2, 3,... so on. The value of magnetic quantum number varies from -l to +l (including zero), it defines the sub shell of electron. Spin of the electron defines its movement that is clockwise or anticlockwise thus, there are only two possible values for spin quantum number: +1/2 or -1/2.

For 2p orbital, principal quantum number n is 2 (denotes the shell) and azimuthal quantum number for p orbital is 1. Thus, different values for magnetic quantum number will be -l to l that is -1, 0,1.

Therefore, for 2p subshell there are 3 different $m_{l}$ values.

5 0

3 years ago

A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.

nata0808 [166]

The equilibrium constant for this reaction at 350°C is determined as 5.85.

<h3>Concentration of each component</h3>

concentration of bromine, C(Br) = 0.6 mol/1 = 0.6

concentration of iodine, C(I) = 1.6 mol/1 = 1.6

<h3>Create an ICE table</h3><h3>What is ICE table?</h3>

An ICE table is a tabular system of keeping track of changing concentrations in an equilibrium reaction.

ICE is an abbreviation that stands for initial, change, equilibrium.

Create ICE table for the reactants and products formed;

Br2(g) + I2(g) ↔ 2IBr(g)

I 0.6 1.6 0

C -1.19 -1.19 1.19

E 0.6 - 1.19 1.6 - 1.19 1.19

E = -0.59 0.41 1.19

<h3>Equilibrium constant </h3>

The equilibrium constant is calculated as follows;

KC = [IBr]²/[Br][I]

KC = (1.19²) / (0.59 x 0.41)

KC = 5.85

Thus, the equilibrium constant for this reaction at 350°C is determined as 5.85.

Learn more about equilibrium constant here: brainly.com/question/19340344

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4 0

2 years ago

How many atoms are found in a 15.5 g sample of bismuth?

r-ruslan [8.4K]

Answer:

4.47 x 10²² atoms

Explanation:

Given parameters:

Mass of Bismuth = 15.5g

Unknown:

Number of atoms = ?

Solution:

To find the number atoms, first solve for the number of moles in this element first.

Number of moles = $\frac{mass}{molar mass}$

Number of moles = $\frac{15.5}{209}$ = 0.074mole

So:

1 mole of a substance contains 6.02 x 10²³ atoms

0.074 mole of Bismuth will contain 0.074 x 6.02 x 10²³ atoms

= 4.47 x 10²² atoms

6 0

3 years ago