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3 years ago

Briefly explain how magnetic behavior is related to the arrangement of valence electrons in the outer orbitals

Chemistry

1 answer:

olga nikolaevna [1]3 years ago

3 0

Answer:

Elements with unpaired valence electrons in the outer orbital are paramagnetic. Elements that are predicted to exhibit paramagnetic behavior may exhibit ferromagnetic behavior. Elements that contain only paired valence electrons are diamagnetic.

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Near the ceiling of a room air is warmer. The warm air rises because of

Amiraneli [1.4K]

Answer:

convection

Explanation:

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4 years ago

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40. What is the mass of 3 moles of H 2 O

Leya [2.2K]

Answer:

54g

Explanation:

Given parameters:

Number of moles of H₂O = 3 moles

Unknown:

mass of water = ?

Solution:

To solve this problem, we use the expression below:

mass = number of moles x molar mass

Molar mass of H₂O = 2(1) + 16 = 18g/mol

Mass of water = 3 x 18 = 54g

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3 years ago

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3 years ago

Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr

VikaD [51]

Answer : The value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

Explanation :

The balanced cell reaction will be,

$Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)$

The half-cell reactions are:

Oxidation reaction (anode) : $Pb(s)\rightarrow Pb^{2+}(aq)+2e^-$

Reduction reaction (cathode) : $2Ag^+(aq)+2e^-\rightarrow 2Ag(g)$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

$\Delta G^o=-2\times 96500\times 0.93$

$\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol$

Now we have to calculate the value of 'K'.

$\Delta G^o=-RT\ln K$

where,

$\Delta G_^o$ = standard Gibbs free energy = -180 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

$-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K$

$K=3.6\times 10^{31}$

Therefore, the value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

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3 years ago

In metallic bonds, the mobile electrons surrounding the positive ions are called a(n)?

Anastaziya [24]

Answer: In metallic bonds, the mobile electrons surrounding the positive ions are called dipole.

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3 years ago