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Artist 52 [7]
3 years ago
10

How does experiments help scientist learn about the world

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Experiments test the scientists' ideas.

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According to the Periodic Table of Elements, Calcium has:
lana [24]

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20 protons and 20 electrons

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DNA in a cell replicates.
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I'm assuming it would be B, since it makes sense. If not, I'm really sorry.

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What does matter have besides mass.
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so like Each of the five states of matter collectively made up all the "stuff" that's in the universe- — everything that takes up space and has mass is matter,and All matter is made up of atoms and in turn made up of protons and neutrons and electrons.

Explanation: hope this helps

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1 year ago
Explain how energy is conserved between this reaction and the and surrounding environment C3H8+4O2->3CO2+4H2O+ heat (-2218.6)
alukav5142 [94]

Answer:

The heat of formation = Heat of formation of the products - Heat of formation of the reactants

= -2323 + 104 = -2219 ≈ -2218.6 kJ/mol.

Explanation:

The law of conservation of energy states that the total energy is constant in any process. Energy may change in form or be transferred from one system to another, but the total remains the same

The heat of formation of C₃H₈ is 3C + 4 H₂ → C₃H₈ \Delta H^{\circ}_f  -104 kJ/mol

The heat of formation of O₂ is O₂ (g) → O₂ (g)  \Delta H^{\circ}_f  0 kJ/mol

The heat of formation of H₂O is H₂(g) + 1/2 O₂→ H₂O (g)  \Delta H^{\circ}_f  -286kJ/mol

The heat of formation of CO₂ is C (s) + O₂ (g) → CO₂ (g)  \Delta H^{\circ}_f  -393 kJ/mol

Therefore, in the given  reaction we have;

C₃H₈ + 4 O₂ → 3 CO₂ + 4 H₂O

The heat of formation = Heat of formation of the products - Heat of formation of the reactants

The heat of formation = 3 × (-393) + 4 × (-286) - (-104) = -2219 ≈ -2218.6 kJ/mol.

5 0
3 years ago
What is the molarity of a solution that contains 3.4 moles of NaCL in 2.2 L of solution ?
jeka94

Answer:

what is the molarity of a solution that contains 3.4 moles of NaCL in 2.2 L of solution ?

Explanation:

5 0
1 year ago
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