<h2><u>
Answer:</u></h2>
0.126 Liters
<h2><u>
Explanation:</u></h2>
V = mRT / mmP
First, convert the 2.25g of Nitrogen gas into moles. (m in the equation above)
2.25g x 1 mole / 28.0g = 0.08036 moles = m
28.0g = mm
Next, convert the 273 Celsius into Kelvin. (T in the equation above)
273 Celsius + 273.15 = 546.15K = T
R = 0.08206L*atm/mol*K
(Quick Note: The R changes depending on the Pressure Unit so do not use this number every time.)
Now, plug everything into the equation.
V = (0.08036)(0.08206)(546.15)/(28.0)(1.02)
V = 0.126 L
Answer:
b) +2 and +3.
Explanation:
Hello,
In this case, given the molecular formulas:
![XO](https://tex.z-dn.net/?f=XO)
And:
![X_2O_3](https://tex.z-dn.net/?f=X_2O_3)
We can relate the subscripts with the oxidation states by knowing that they are crossed when the compound is formed, for that reason, we notice that oxygen oxidation state should be -2 for both cases and the oxidation state of X in the first formula must be +2 since both X and O has one as their subscript as they were simplified:
![X^{+2}O^{-2}](https://tex.z-dn.net/?f=X%5E%7B%2B2%7DO%5E%7B-2%7D)
Moreover, for the second case the oxidation state of X should be +3 in order to obtain 3 as the subscript of oxygen:
![X_2^{+3}O_3^{-2}](https://tex.z-dn.net/?f=X_2%5E%7B%2B3%7DO_3%5E%7B-2%7D)
Thus, answer is b)+2 and +3
Best regards.
Moles of N2O5 = moles of NO2 * ( 2 moles of N2O5 / 4 moles of NO2
Answer:
A.It is the same for every sample of a single substance.
Explanation: