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3 years ago

3.0E-17 joules divided by 1.0E -27 kgm/s equals?

Physics

1 answer:

insens350 [35]3 years ago

7 0

Here we have two physical quantities which we have to divide

$P_1 = 3.0 \times 10^{-17} J$

other is

$P_2 = 1.0 \times 10^{-27} kg m/s$

now we need to find its division

$\frac{P_1}{P_2} = \frac{3.0\times 10^{-17}}{1.0\times 10^{-27}}$

now we have

$\frac{P_1}{P_2} = 3.0\times 10^{10} Js/kgm$

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The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

time of fall of the first ball, t = 1 s
time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

$h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m$

The distance traveled by the second ball is calculated as follows;

$h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m$

Thus, the second ball traveled a greater distance because it spent more time in motion.

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snow_lady [41]

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