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3 years ago

3.0E-17 joules divided by 1.0E -27 kgm/s equals?

Physics

1 answer:

insens350 [35]3 years ago

7 0

Here we have two physical quantities which we have to divide

$P_1 = 3.0 \times 10^{-17} J$

other is

$P_2 = 1.0 \times 10^{-27} kg m/s$

now we need to find its division

$\frac{P_1}{P_2} = \frac{3.0\times 10^{-17}}{1.0\times 10^{-27}}$

now we have

$\frac{P_1}{P_2} = 3.0\times 10^{10} Js/kgm$

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In your own words, explain how Doppler radar works. Describe the properties of electromagnetic waves and interactions that make

lisov135 [29]

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3 years ago

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How many kcalories are provided by a food that contains 25 g carbohydrate, 6 g protein, and 5 g fat?

MrRissso [65]

<u>169 Kcalories</u> are provided by a portion of food that has 25 grams of carbs, 6 grams of protein, and 5 grams of fat.

Kcalories mean kilo-calories. Basically, kilo-calorie or kcal refers to 1,000 calories. To get the Kcalories of food, you have to add the kcal of carbohydrates, protein, and fat.

Get the product by multiplying the number of grams of carbohydrate, protein, and fat by 4,4, and 9, respectively. So if you want to get the energy or Kcal available from a meal, you must then combine the outcomes.

Simply put it, take note of the following conversions:

1 gram of carbohydrate is 4kcal
1 gram of protein is also 4kcal
Though, 1 gram of fat is 9kcal

So here's how to compute the Kcalories of food that contains 25g carbs, 6g protein, and 5g fat.

1. 25g x 4kcal/g = 100kcal

2. 6g x 4kcal/g = 24kcal

3. 5g x 9kcal/g = 45kcal

4. 100kcal + 24kcal + 45kcal = 169kcal!

Therefore, the food contains 169 kilo-calories!

You might be interested in nutrient density of an orange juice per kcalorie. Look here: brainly.com/question/26495283

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2 years ago

A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4

irina [24]

Here We can use principle of angular momentum conservation

Here as we know boy + projected mass system has no external torque

Since there is no torque so we can say the angular momentum is conserved

$mvL = (I + mL^2)\omega$

now we know that

m = 2 kg

v = 2.5 m/s

L = 0.35 m

I = 4.5 kg-m^2

now plug in all values in above equation

$2\times 2.5 \times 0.35 = (4.5 + (2\times 0.35^2))\omega$

$1.75 = [4.5 + 0.245]\omega$

$1.75 = 4.745\omega$

$\omega = 0.37 rad/s$

so the final angular speed will be 0.37 rad/s

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3 years ago

Is this statement true or false?

RSB [31]

Answer:

Places at the same latitude may have very different climates if one is on a coast and one is inland. On the coast, the climate is influenced by warm moist air from the ocean. A coastal climate is usually mild. ... Farther inland, the climate is influenced by cold or hot air from the land.

Explanation:

Hopefully its correct!

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3 years ago

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A ball is thrown straight up at time t=0 with an initial speed of 19m/s. Take the point of release to be y0=0 and upwards to be

Wittaler [7]

First we write the corresponding kinematics equations:
a = -g
v = -g * t + vo
y = -g * ((t ^ 2) / 2) + vo * t + yo
Substituting the values:
y = - (9.81) * (((0.50) ^ 2) / 2) + (19) * (0.50) + (0) = 8.27m
answer:
the displacement at the time of 0.50s is 8.27m

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3 years ago