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3 years ago

consider the mirror from the last question. an object 4cm tall stands 10cm in front of a converging mirror of focal length 5cm.

Physics

2 answers:

aleksandr82 [10.1K]3 years ago

6 0

<span>An Object 4 Cm Tall Is Placed 12 Cm From A Divergi... | Chegg.com</span>

RSB [31]3 years ago

4 0

Answer:

This question is incomplete, here is the complete question;

"Consider the mirror shown here. An object 4 cm tall stands 10 cm in front of a converging mirror of focal length 5 cm.

The image formed by this mirror is: (Select all that apply.)

real

virtual

enlarged

the same size

diminished

Inverted

erect"

Answer: Virtual, Upright and Enlarged

Explanation:

The formula for image formed by a converging mirror is given by;

$\frac{1}{f} =\frac{1}{u} +\frac{1}{v}$ ------------------- eqn 1

where f = focal length = 5 cm

u = object height = 4 cm

v = image height = ?

substitute for u and f in eqn 1 to find v.

$\frac{1}{5} =\frac{1}{4} +\frac{1}{v}$

$\frac{1}{v} =\frac{1}{5} -\frac{1}{4}$

v = -20 cm

From the value of the image formed i.e -20 cm

The negative sign means the image is behind the mirror and this means image is;

1. Virtual

2. Upright

3. Enlarged

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