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den301095 [7]
4 years ago
13

Answer is needed asap

Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
7 0
I think it is letter A ,man. yeah that gotta be the answer


Svet_ta [14]4 years ago
7 0
Since Landon has 4 times as more just divide 16 by 4.

The answer is B.

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What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract
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Answer:

|z| = 27 -- Modulus

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Step-by-step explanation:

Given

((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Required

Determine the modulus and the argument

We have that:

z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Expand:

z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

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A complex equation can be expressed as:

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Where

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So:

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6 becomes

z = 27(e^{i\frac{\pi}{18}})^6

By comparison:

e^{i\theta} = (e^{i\frac{\pi}{18}})^6

This gives:

{i\theta} = i\frac{\pi}{18}}*6

{i\theta} = i\frac{6\pi}{18}}

{i\theta} = i\frac{\pi}{3}}

Divide through by i

\theta = \frac{\pi}{3}

Hence, the modulus, z is:

|z| = 27

And the argument \theta is

\theta = \frac{\pi}{3}

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