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3 years ago

12

I stand 0.72 meters in front of a mirror and look at the person on the other side who looks like me. That person is actually you

nger than me by a small amount. How much?

1 answer:

Sergeu [11.5K]3 years ago

4 0

Answer:

Younger by nanoseconds

Explanation:

Not entirely sure :O

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A 6.7 kg object moves with a velocity of 8 m/s. What's its kinetic energy? A. 26.8 J B. 214.4 J C. 167.5 J D. 53.6 J

expeople1 [14]

KE= .5*M*V^2
.5*6.7*8^2
=214.4 Joules

7 0

4 years ago

Read 2 more answers

A shark is in the ocean trying to catch fish. If the shark swims to the right for 30 meters, then swims to the left for 15 meter

almond37 [142]

Answer:

65 meters to the right.

Explanation:

the shark moves to the right 30 meters and then to the left 15 making his new placement 15. he then moved to the right 50 meters making his new placement 65 meters to the right.

6 0

3 years ago

A 1,500 kg car’s speed changes from 30 m/s to 15 m/s after the brakes are applied. Calculate the work done onto the car from the

HACTEHA [7]

The work done onto the car is 506,250 J

The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.

From the parameters given:

The mass of the car = 1500 kg
The initial speed = 30 m/s
The final speed = 15 m/s

The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)

$\mathbf{=\dfrac{1}{2} mv_1^2 -\dfrac{1}{2} mv_2^2}$

$\mathbf{=\dfrac{1}{2} m(v_1^2 - v_2^2)}$

$\mathbf{=\dfrac{1}{2} \times 1500 \times (30^2 - 15^2)}$

= 506,250 J

Therefore, we can conclude that the work done on the car is 506,250 J

Learn more about work done here:

brainly.com/question/18762601

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3 years ago

About 30 % of earth’s water found In

Illusion [34]

Answer:

30 percent is found in ground water.

6 0

3 years ago

At a distance of 8 m, the sound intensity of one speaker is 66 dB. If we were to place 3 speakers in a circle of radius 8 m, wha

ludmilkaskok [199]

Answer:

dβ = 70. 77 dβ

Explanation:

The intensity of sound in decibels is

dβ = 10 log I/I₀

let's look for the intensity of this signal

I / I₀ = 10 dβ/10

I / I₀ = 3.981 10⁶

the threshold intensity of sound for humans is I₀ = 1 10⁻¹² W / m²

I = 3.981 10 ⁶ 1 10⁻¹²

I = 3,981 10⁻⁶ W / m²

It is indicated that 3 cornets are placed in the circle, for which total intensity is

I_total - 3 I

I_total = 3 3,981 10⁻⁶

I_total = 11,943 10⁻⁶ W / m²

let's reduce to decibels

dβ = 10 log (11,943 10⁻⁶/1 10⁻¹²)

dβ = 10 7.077

dβ = 70. 77 dβ

3 0

3 years ago