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12345 [234]
4 years ago
13

Petroleum is a nonrenewable resource. true or false

Physics
1 answer:
Nata [24]4 years ago
5 0
Coal, petroleum, and natural gas are considered nonrenewable because they can not be replenished in a short period of time
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What type of reaction is being shown in this energy diagram?
prisoha [69]
Answer is C because I’m exothermic energy products are always lower than reactants
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2 years ago
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What regulatory requirements must be met prior to a pilot acting as PIC of an aircraft towing a glider?
Klio2033 [76]

Answer:

According to the federal aviation regulation for tow pilot, there are three regulatory requirements to be met.

Explanation:

1. The Pilot must hold at least a private pilot certificate with a category rating for powered aircraft.

2. The Pilot must have logged at least 100 hours of pilot-in-command time in the aircraft category.

3. The Pilot must have a logbook endorsed by an authorized instructor who certifies that the person has received ground and flight training in gliders and is proficient in the following;

a. Procedures and techniques of safe towing of gliders.

b. Signal use.

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4 years ago
In the seventeenth century, Robert Hooke conducted many experiments with springs. In all the data he recorded, he found that the
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The explanation of the relationship between load and extension is not in Hooke's Law.
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4 years ago
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Bone has a Young's modulus of about
saveliy_v [14]

Answer: 4.74 mm

Explanation:

We can solve this problem with the following equation:

Y=\frac{stress}{strain} (1)

Where:

Y=1.8(10)^{10} Pa is the Young modulus for femur

stress=\frac{F}{A}=1.58(10)^{8} Pa is the stress (force F applied per unit of transversal area A) on the femur

strain=\frac{\Delta l}{l_{o}}

Being:

\Delta l the compression the femur can withstand before breaking

l_{o}=0.54 m is the length of the femur without compression

Writing the data in equation (1):

Y=\frac{\frac{F}{A}}{\frac{\Delta l}{l_{o}}} (2)

1.8(10)^{10} Pa=\frac{1.58(10)^{8} Pa}{\frac{\Delta l}{0.54 m}} (3)

Isolating \Delta l:

\Delta l=\frac{(1.58(10)^{8} Pa)(0.54 m)}{1.8(10)^{10} Pa} (4)

\Delta l=0.00474 m (5) This is the compression in meters

Converting this result to millimeters:

\Delta l=0.00474 m \frac{1000 mm}{1 m}=4.74 mm

4 0
4 years ago
What is the primary difference between an ideal emf device and a real emf device?.
EleoNora [17]

Answer:

A real emf device has an internal resistance, but an ideal emf device does not.

3 0
2 years ago
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