Answer:
I = 
(K+5)
Explanation:
Given :
J = k+5
Now selecting a thin ring in the wire of radius "r" and thickness dr.
Current through the thin ring is
dI = J X 2πrdr
dI = (K+5) x 2πrdr
Now integrating we get
I = 
I = (K+5) 2π
I = (K+5) 2π 
I = (K+5)
Answer:
12N
Explanation:
We are given that one of the forces are acting only in the horizontal x-direction. As a force must be applied on an object of mass in order to cause acceleration, the 6.0ms^-2 acceleration is due to the non-horizontal force acting on the 2.0kg object.
Using Newton's Second Law of motion; we know that for a constant mass, force is equal to mass times acceleration, F=ma.
Assuming the other force is acting only in the vertical direction (question doesn't specify, thus we are finding the minimum force to cause this acceleration):
F= 2.0kg * 6.0ms^-2
F=12.0 kgms^-2
F=12 N
Answer:
.012
Explanation:
Take the mass of the fish and divide it by the mass of the water:
65/.30=216.667
Divide the given speed by the value we found above:
2.5/216.667=.0115
Answer can be rounded up to .012
