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nirvana33 [79]
3 years ago
14

imagine that a tank is filled with water the hight of the liquid column is 7 meters and the area is 1.5 sq meters (m™). what's t

he force of gravity acting on the column of water.
Physics
1 answer:
Annette [7]3 years ago
8 0
Answer - 12,900 Newtons

Explanation

First, we find the volume of the water
Volume = Area * Heinght
= 1.5 m² x 7 m
=  10.5 m³
 
Covert the volume to liters
1 m³ of water = 1000  liters
10.5 m³ of water = 10.5 m³ * 1000 liters liter/m³
= 10,500 liters
 
Use the volume of water to calculate the mass
1 liter of water weighs 1 kg
10,500 liters of water = 10,500 * 1 kg/liter
= 10,500 kg
 
Now, we can calculate the force of gravity on the water
Force of gravity on the water = Weight of the water
Weight = Mass * Acceleration
 
Mass = 10,500kg
Acceleration (due to gravity) = 9.8 m/s²

Force of gravity on the water
= Weight of the water
= Mass * Acceleration
= 10,500 kg * 9.8 m/s²
 = 102,900 Newtons 
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KE = 0.5mv^2

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KE = 0.5mv^2
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Can someone please give me the (Answers) to this? ... please ...<br><br> I need help….
IceJOKER [234]

#1.

<em>Car </em>1<em> weighs </em>300 kilograms<em> and is moving right at </em>3 meters per second (m/s)

  • v1 (before) = 3 m/s

  • v2 (before) = -1 m/s

  • v1 (after) = 0.5 m/s

#2.

Law of conservation of momentum

momentum before collorion = momentim after collosion

MV + mv = MV' + mv'

1500x25+ 1000x5

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2 years ago
Three rocks with masses of 1 kg, 5 kg, and 10 kg fall from the same height.
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Answer:
The 10 kg rock has more inertia than the other two rocks.


Explanation
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A passenger train travels 392 mi in the same time that it takes a freight train to travel 322 mi. If the passenger train travels
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Answer:

Explanation:

Given

distance traveled by  Passenger train is d_1=392\ mi

distance traveled by  Freight train is d_2=322\ mi

Both take same time to travel

suppose speed of freight train is x mph

so speed of passenger train is 20+x mph

we know time=\frac{distance}{speed}

t=\frac{392}{20+x}=\frac{322}{x}

392x=322x+322\times 20

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x=92\ mph

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You need to focus a 10 mW, 632.8 nm Gaussian laser beam that is 5.0 mm in diameter into a sample. You have access to a lens with
Anna [14]

Answer:

ee that the lens with the shortest focal length has a smaller object

           

Explanation:

For this exercise we use the constructor equation or Gaussian equation

        \frac{1}{f}  = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distance to the object and the image respectively.

Magnification a lens system is

          m = \frac{h'}{h} = - \frac{q}{p}

             h ’= -\frac{h q}{p}

In the exercise give the value of the height of the object h = 0.50cm and the position of the object p =∞

Let's calculate the distance to the image for each lens

f = 6.0 cm

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as they indicate that the light fills the entire lens, this indicates that the object is at infinity, remember that the light of the laser rays is almost parallel, therefore p = inf

          q = f = 6.0 cm

for the lens of f = 12.0 cm q = 12.0 cn

to find the size of the image we use

           h ’= h q / p

where p has a high value and is the same for all systems

           h ’= h / p q

Thus

f = 6 cm h ’= fo 6 cm

 

f = 12 cm h ’= fo 12  cm

therefore we see that the lens with the shortest focal length has a smaller object

8 0
3 years ago
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