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3 years ago

A metaphor is:

1 answer:

6 0

A metaphor is a comparison between two non related objects where the first object is said to be equal to the second.

The answer is d.

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A ball is shot at an angle of 45 degrees into the air with initial velocity of 46 ft/sec. Assuming no air resistance, how high d

mestny [16]

Answer:

5.02 m

Explanation:

Applying the formula of maximum height of a projectile,

H = U²sin²Ф/2g...................... Equation 1

Where H = maximum height, U = initial velocity, Ф = angle, g = acceleration due to gravity.

Given: U = 46 ft/sec = 14.021 m/s, Ф = 45°

Constant: g = 9.8 m/s²

Substitute these values into equation 1

H = (14.021)²sin²45/(2×9.8)

H = 196.5884×0.5/19.6

H = 5.02 m.

Hence the ball goes 5.02 m high

8 0

3 years ago

Transformer is used in rectifier step up and step down voltage?

tensa zangetsu [6.8K]

Answer:

While the use of the type of transformer in a rectifier depends on the voltage requirement or to meet desired operating conditions, a step-down transformer is used mainly to reduce the voltage. It is used to bring the high AC voltage level to a reasonable value or the desired output voltage.

Explanation:

Hope it helps

Correct me if Im wrong

3 0

2 years ago

A bus starts from rest.if the acceleration is 2m/s square, find

MrMuchimi

Answer:

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

V^2= u^2 +2*a* s

Where V is final velocity, u is initial velocity, a is acceleration.

4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

s= ut + 1/2 at^2

s= 0+ 1/2 *2*2^2= 1 *2*2

s= 4 meters

Explanation:

3 0

2 years ago

Why should scientist data be written in ink ? I need major help plz :)

Kobotan [32]

Because they are legal documents they can be used in a court of law

3 0

3 years ago

A lamp in a child's Halloween costume flashes based on an RC discharge of a capacitor through its resistance. The effective dura

Genrish500 [490]

Power of the lamp = (voltage) x (current)

0.62 watt = (3.0 v) x (current)

Current = (0.62 watt) / (3.0 volt)

Current = 0.207 Ampere

Charge = (current) x (time)

Charge = (0.207 Amp) x (0.32 sec)

a). Charge = 0.066 Coulomb

Energy discharge through the lamp = (charge) x (voltage)

Energy = (0.66 C) x (3.0 volt)

Energy = 0.1984 Joule

Energy stored in a capacitor = (1/2) (Capacitance) (voltage²)

0.1984 Joule = (1/2) (Cap) (3.0 v)²

Cap = 2 x 0.1984 / 9

b). Cap = 0.044 Farad (yikes !)

Resistance of the lamo = (voltage) / (current)

Resistance = (3.0 volt) / (0.207 Amp)

c). Resistance = 14.49 Ω

All of this feels OK except for that ridiculous 44,000 μF, 3v capacitor. Sadly, I have checked my work without finding an error, and I am too lazy to check it again. So I'll call this my final answer, and leave it to some better Brainly person to find where I went wrong.

6 0

4 years ago