1 x 10⁻¹¹m²
Explanation:
Given parameters:
Resistivity = 100 x 10⁻⁶Ohm.m
Cross-section = 1mm²
Resistance = 10ohm
Unknown:
length of the nichrome wire = ?
Solution:
To find the length of the nichrome wire, we use the expression below:
L =
where l is the length of the wire
R is the resistance of the wire
A is the area
p is the resistivity
Now we need to convert area from mm to m;
1000mm = 1 m
1mm² = 1 x = 1 x 10⁻⁶m²
Input the values in the formula;
L = = 1 x 10⁻¹¹m²
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Answer:
The correct option is C
Explanation:
According to third equation of motion, v
2
=u
2
+2ax
Here, u=0 m/s
a=−g and x=−h
Negative sign indicates downward direction. Displacement and acceleration both are downwards.
So,v=±
2(−g)(−h)
We take minus sign because it is downwards.
v=−
2gh
After bouncing. velocity becomes 80% of v, i.e.,
v
′
=+0.8
2gh
(positive sign because the direction of ball has reversed after bouncing and is upwards.
Applying third equation of motion again, for u=v
′
, v=0 and a=−g
v
2
=u
2
+2×a×x
Thus,
0=0.64(2gh)+2(−g)x
or
x=0.64h
The equation is not balance because the law of conservation of mass is not being followed.
<h3>Why the equation is not balanced?</h3>
The hydrogen and chlorine atoms have different numbers of atoms in the reactants and products which is not balance on both sides i.e. reactant and products.
So we can conclude that the equation is not balance because the law of conservation of mass is not being followed.
Learn more about equation here: brainly.com/question/2972832
It is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.
<h3>What is Gravitational interaction?</h3>
This is defined as the interaction between a particle or body resulting from their mass. This type of interaction is usually weak and occurs in all distances possible.
It is not gravitational interaction, because the rod attracts paper only against the gravitational force of the earth and there is no attraction between both bodies under a different condition.
This is therefore the reason why it is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.
Read more about Gravitational interaction here brainly.com/question/25624188
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