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NikAS [45]
3 years ago
14

Haley is trying to pull an object upward. The below forces are acting on the object.

Physics
2 answers:
bulgar [2K]3 years ago
7 0

Answer:

↓ 500N

Explanation:

worty [1.4K]3 years ago
3 0

Answer:

↓ 500N

Explanation:

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A 300 MHz electromagnetic wave in air (medium 1) is normally incident on the planar boundary of a lossless dielectric medium wit
Masja [62]

Answer:

Wavelength of the incident wave in air = 1 m

Wavelength of the incident wave in medium 2 = 0.33 m

Intrinsic impedance of media 1 = 377 ohms

Intrinsic impedance of media 2 = 125.68 ohms

Check the explanation section for a better understanding

Explanation:

a) Wavelength of the incident wave in air

The frequency of the electromagnetic wave in air, f = 300 MHz = 3 * 10⁸ Hz

Speed of light in air, c =  3 * 10⁸ Hz

Wavelength of the incident wave in air:

\lambda_{air} = \frac{c}{f} \\\lambda_{air} = \frac{3 * 10^{8} }{3 * 10^{8}} \\\lambda_{air} = 1 m

Wavelength of the incident wave in medium 2

The refractive index of air in the lossless dielectric medium:

n = \sqrt{\epsilon_{r} } \\n = \sqrt{9 }\\n =3

\lambda_{2} = \frac{c}{nf}\\\lambda_{2} = \frac{3 * 10^{6} }{3 * 3 * 10^{6}}\\\lambda_{2} = 1/3\\\lambda_{2} = 0.33 m

b) Intrinsic impedances of media 1 and media 2

The intrinsic impedance of media 1 is given as:

n_1 = \sqrt{\frac{\mu_0}{\epsilon_{0} } }

Permeability of free space, \mu_{0} = 4 \pi * 10^{-7} H/m

Permittivity for air, \epsilon_{0} = 8.84 * 10^{-12} F/m

n_1 = \sqrt{\frac{4\pi * 10^{-7}  }{8.84 * 10^{-12}  } }

n_1 = 377 \Omega

The intrinsic impedance of media 2 is given as:

n_2 = \sqrt{\frac{\mu_r \mu_0}{\epsilon_r \epsilon_{0} } }

Permeability of free space, \mu_{0} = 4 \pi * 10^{-7} H/m

Permittivity for air, \epsilon_{0} = 8.84 * 10^{-12} F/m

ϵr = 9

n_2 = \sqrt{\frac{4\pi * 10^{-7} *1 }{8.84 * 10^{-12} *9 } }

n_2 = 125.68 \Omega

c) The reflection coefficient,r  and the transmission coefficient,t at the boundary.

Reflection coefficient, r = \frac{n - n_{0} }{n + n_{0} }

You didn't put the refractive index at the boundary in the question, you can substitute it into the formula above to find it.

r = \frac{3 - n_{0} }{3 + n_{0} }

Transmission coefficient at the boundary, t = r -1

d) The amplitude of the incident electric field is E_{0} = 10 V/m

Maximum amplitudes in the total field is given by:

E = tE_{0} and E = r E_{0}

E = 10r, E = 10t

3 0
3 years ago
Which only list metalloids
HACTEHA [7]

Answer: I think the answer <em><u>MIGHT</u></em> be: Boron, germanium, and tellurium....

Explanation:I know this cuz I had this question on my unit test and I had to look it up online....Hope this helps

I really hope you guys find this helpful and thx so much for rating :D

       pls say something in chat if you found this helpful

                                              UwU           ;-;

                                                         

7 0
3 years ago
A 1000-kg car is moving at 40.0 km/hr when the driver slams on the brakes and skids to a stop (with locked brakes) over a distan
liq [111]

Answer:

 skid distance = 180 m  

Explanation:

given,

mass of the car = 1000 Kg

speed of the car = 40 Km/hr

distance to stop = 20 m

if speed is now = 120 Km/he

distance to stop = ?

from given question we can state that,

Work done by the friction is equal to the change in kinetic energy of the car.

       W= \dfrac{1}{2}mv^2............(1)

And we also know that work is directly proportional to displacement

               W = F × x...........................(2)

from the equation (1) and (2)

        x ∝ v²

now,

   here velocity is increased from 40 km/h to 120 km/h means velocity is increase 3 times

so displacement will be equal to 3² or 9 times

hence, skid distance will be equal to 9 x 20 = 180 m

 skid distance = 180 m  

8 0
3 years ago
Please help answer #14!!!!!!!
jeka94

When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.

Hope this helps you!!!

Please mark this as the brainliest one!!!

7 0
3 years ago
Explain how refraction and prisms work.
Liono4ka [1.6K]
A prism is a piece of glass or plastic in the shape of a triangle. A prism works because the different colors of light travel at different speeds inside the glass. Because the colors of light travel at different speeds, they get bent by different amounts and come out all spread out instead of mixed up.


Refraction is the bending of a wave when it enters a medium where its speed is different. The refraction of light when it passes from a fast medium to a slow medium bends the light ray toward the normal to the boundary between the two media. Refraction is responsible for image formation by lenses and the eye.
8 0
4 years ago
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