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frez [133]
3 years ago
7

3. A 1500 kg car moving at 30 m/s strikes a 6000 kg van initially at rest. If the car

Physics
1 answer:
MissTica3 years ago
3 0

Answer:

7.5m/s

Explanation:

Force= mass × velocity

Energy is conserved, the car and van should have the same overall force.

1500kg × 30m/s= 6000kg × final velocity

Final velocity = 7.5m/s

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Explain what surface tension is.
sergejj [24]
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5 0
3 years ago
Read 2 more answers
The pulley system below uses a gasoline engine to raise a drill head up through a smooth drill pipe. The engine provides a const
polet [3.4K]

NB: The diagram of the pulley system is not shown but the information provided is sufficient to answer the question

Answer:

Power = 2702.56 W

Explanation:

Let the power consumed be P

Energy expended = E = mgh

height, h = 5 m

E = 80 * 9.8 * 5

E = 3920 J

Power = \frac{Energy}{time}

To calculate the time, t

From F = ma

F = 900 N

900 = 80 a

a = 900/80

a = 11.25 m/s²

From the equation of motion, s = ut + 0.5at^{2}

The drill head starts from rest, u = 0 m/s

5 = 0 * t + (0.5*11.25*t^{2} )\\5 = 5.625t^{2}\\t^{2} = 5/5.625\\t^{2} = 0.889\\t = 0.943 s

Power, P = E/t

P = 3920/0.0.943

P = 4157.79 W

But Efficiency, E = 0.65

P = 0.65 * 4157.79

Power = 2702.56 W

6 0
3 years ago
If a wave’s frequency is 16Hz and it’s wavelength is 10m. What’s the waves speed?
Vesna [10]

Answer:

160J

Explanation:

Given parameters:

Frequency  = 16Hz

Wavelength = 10m

Unknown:

Waves speed  = ?

Solution:

Waves speed is the product of frequency and wavelength;

  Waves speed  = fλ

f is the frequency

λ is the wavelength

Now insert the parameters and solve;

     Waves speed = 16 x 10  = 160J

4 0
3 years ago
4.A 13.6 kg bag of dog food is held 1.25 m above the ground. Calculate the
Tanzania [10]

Answer:

PE = mgh = 13.6(9.81)(1.25) = 166.77 ≈ 167 J

Explanation:

5 0
3 years ago
A student stays at her initial position for a bit of time, then walks slowly in a straight line for a while, then stops to rest
True [87]

Answer:

The first interval is walked slowly, this is a straight line with a small slope

Second interval stops, which gives a horizontal line, indicating the same position

Third interval, walk back, straight downhill

Explanation:

In this problem we have a uniform movement, this means that the acceleration in each intervals

              x = v t

 

The first interval is walked slowly, this is a straight line with a small slope

Second interval stops, which gives a horizontal line, indicating the same position

Third interval, walk back, straight downhill

6 0
3 years ago
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