Answer:
Explanation:
Area of a circular hubcap is 615 square inches
Area of a circular shaped object is given by :

r is radius of hubcap.
If the radius of the hubcap were quadrupled, it means r' = 4r. New area will become:

A' is new area

New area of the hubcap is 9840 square inches.
Although it has a negative charge, it will never accept a
H
+
to form
H
2
S
O
4
(sulfuric acid) . That is because sulfuric acid is a strong acid and completely disassociates in water.
Therefore, the sulfate ion (
S
O
2
−
4
) is the conjugate base of
H
S
O
−
4
.
Answer:
Percent error = 5.6%
Explanation:
Given data:
Measured value of density by students = 2.85 g/cm³
Accepted density of aluminium = 2.70 g/cm³
Percent error = ?
Solution:
Formula:
Percent error = [ Measured value - accepted value / accepted value ]× 100
Now we will put the values in formula:
Percent error = [ 2.85 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ]× 100
Percent error = [0.15/2.70 g/cm³ ] × 100
Percent error = 0.056× 100
Percent error = 5.6%
It has six significant figures. You count the 0s that come at the end because it shows you it wasn't rounded.
Answer:
a. 
b. 
Explanation:
Hello,
a. In this case, the overall reaction is:

Nevertheless, the ionic version is:

Since the base is insoluble, thereby, the balanced net ionic equation turns out:

Since bromide ions become spectator ions.
b) In this case, the overall reaction is:

Nevertheless, the ionic version is:

Since lead (II) iodide is insoluble whereas lithium nitrate does not, thereby, the net ionic equation turns out:

Since lithium and nitrate ions become spectator ions.
Regards.