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Makovka662 [10]

4 years ago

8

Help quickly pleaseeeeeeee

1 answer:

blsea [12.9K]4 years ago

8 0

Answer:

1. 8 ph

2. H+ ions

Explanation:

For #1, since the acid and bases are both the same quantity, the ph of the whole mixture would be the average of the two, or 8.

For #2, acids are compounds that dissociate (break) into hydrogen (H+) ions and another compound when placed in an aqueous solution.

Hope that helped! :)

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19 What is the "skin" of the cell?

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3 years ago

A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to

katen-ka-za [31]

I wrote the answer on this paper and here is the calculations step by step

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3 years ago

Read 2 more answers

15g of sugar and 10g of water are measured separately. The sugar is dissolved in the water. What will

quester [9]

Answer: a) No, both are different.

b) Ramesh- 9.9%

Sarika - 10%

Explanation:

According to the solution prepared by Ramesh,

Mass of sugar he took (Solute) = 10 g

Mass of water he took (Solvent) = 100 g

Thus Mass % of the solution =

According to the solution prepared by Sarika,

Mass of sugar she took (Solute) = 10 g

Mass of Solution she took = 100 g

Thus Mass % of the solution =

Explanation:

7 0

3 years ago

. The Henry's law constant for helium gas in water at 30 ∘C is 3.7×10−4M/atm; the constant for N2 at 30 ∘C is 6.0×10−4M/atm. a.

ludmilkaskok [199]

Explanation:

1) Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$M_{g}=K_H\times p_{g}$

where,

$K_H$ = Henry's constant

$p_{He}$ = partial pressure of gas

a) $K_H=3.7\times 10^{-4} M/atm$

$p_{He}=2.1 atm$

Putting values in above equation, we get:

$M_{He}=3.7\times 10^{-4} M/atm\times 2.1 atm = 7.77\times 10^{-4} M$

The solubility of helium gas is $7.77\times 10^{-4} M$

b) $K_H=6.0\times 10^{-4} M/atm$

$p_{N_2}=2.1 atm$

Putting values in above equation, we get:

$M_{He}=6.0\times 10^{-4} M/atm\times 2.1 atm = 1.26\times 10^{-3} M$

The solubility of nitrogen gas is $1.26\times 10^{-3} M$

2)

a) Mass of solute or methanol , m= 14.7 g

Mass of solvent or water , m'= 186 g

Mass of the solution = M = m + m' = 14.7 g + 186 g = 200.7 g

$w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

$=\frac{14.7 g}{200.7 g}\times 100=7.32\%$

The mass percent of methanol is 7.32%.

b) Molality is defined as moles of solute per kilograms of solvent.

$m=\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}$

Moles of methanol = $\frac{14.7 g}{32 g/mol}=0.4594 mol$

Mass of solvent = 186 g = 0.186 kg

$m=\frac{0.4594 mol}{0.186 kg}=2.4610 mol/kg$

The molality of methanol is 2.4610 mol/kg.

4 0

3 years ago