I can help you draw the ray diagram.
If Aldebaran were to explode tonight then we will be able to see this explosion on the Earth in approximately 65 years. A light-year is a distance that light travels in one (1) year.
<h3>What is a light-year?</h3>
A light-year can be defined as a unit equal to the distance that light needs to travels in one (1) year on the Earth.
One light-year can be considered as a unit that equates to approx. 9.7 trillion kilometers (km) or 5.9 trillion miles.
In consequence, a light-year is a distance unit instead of a unit of time, and this unit was developed by Otto Ule.
Learn more about the light-year unit here:
brainly.com/question/1224192
No. Only velocity depends on direction.
Answer:
U = 5.37*10^33 J
Explanation:
The gravitational potential energy between two bodies is given by:
![U_{1,2}=-G\frac{m_1m_2}{r_{1,2}}](https://tex.z-dn.net/?f=U_%7B1%2C2%7D%3D-G%5Cfrac%7Bm_1m_2%7D%7Br_%7B1%2C2%7D%7D)
G: Cavendish's constant = 6.67*10^-11 m^3/kg.s
For three bodies the total gravitational potential energy is:
![U_{T}=U_{1,2}+U_{1,3}+U_{2,3}\\\\U_{T}=-G[\frac{m_1m_2}{r_{1,2}}+\frac{m_1m_3}{r_{1,3}}+\frac{m_2m_3}{r_{2,3}}]](https://tex.z-dn.net/?f=U_%7BT%7D%3DU_%7B1%2C2%7D%2BU_%7B1%2C3%7D%2BU_%7B2%2C3%7D%5C%5C%5C%5CU_%7BT%7D%3D-G%5B%5Cfrac%7Bm_1m_2%7D%7Br_%7B1%2C2%7D%7D%2B%5Cfrac%7Bm_1m_3%7D%7Br_%7B1%2C3%7D%7D%2B%5Cfrac%7Bm_2m_3%7D%7Br_%7B2%2C3%7D%7D%5D)
BY replacing the values of the parameters for 1->earth, 2->moon and 3->sun you obtain:
![U_{T}=-(6.67*10^{-11}m^3/kg.s)[\frac{(5.98*10^{24}kg)(7.36*10^{22}kg)}{3.84*10^{8}m}+\\\\\frac{(5.98*10^{24}kg)(1.99*10^{30}kg)}{1.496*10^{11}m}+\frac{(7.36*10^{22}kg)(1.99*10^{30}kg)}{1.496*10^{11}m-3.84*10^8m}]\\\\U_{T}=5.37*10^{33}J](https://tex.z-dn.net/?f=U_%7BT%7D%3D-%286.67%2A10%5E%7B-11%7Dm%5E3%2Fkg.s%29%5B%5Cfrac%7B%285.98%2A10%5E%7B24%7Dkg%29%287.36%2A10%5E%7B22%7Dkg%29%7D%7B3.84%2A10%5E%7B8%7Dm%7D%2B%5C%5C%5C%5C%5Cfrac%7B%285.98%2A10%5E%7B24%7Dkg%29%281.99%2A10%5E%7B30%7Dkg%29%7D%7B1.496%2A10%5E%7B11%7Dm%7D%2B%5Cfrac%7B%287.36%2A10%5E%7B22%7Dkg%29%281.99%2A10%5E%7B30%7Dkg%29%7D%7B1.496%2A10%5E%7B11%7Dm-3.84%2A10%5E8m%7D%5D%5C%5C%5C%5CU_%7BT%7D%3D5.37%2A10%5E%7B33%7DJ)
hence, the total gravitational energy is 5.37*10^33 J
Xf=?
Xi=0m
Vi=0m/s
Vf=40m/s
a=?
t=12s
Xf=Xi+1/2(Vi+Vf)t
Xf= 0 +1/2 (0+40)12
Xf=1/2 (40)12
Xf=240m
Vf=Vi+at
40=0+a (12)
40=12a
a=3.33m/s^2